Answer:
v ≈ 4.47
Explanation:
The Formula needed = <u>KE = </u><u> m v²</u>
<u></u>
Substitute with numbers known:
2000J = × 200kg × v²
Simplify:
÷100 ÷100 (Divide by 100 on both sides)
2000J = 100 × v²
= v²
20 = v²
√ √ (Square root on both sides)
√20 = √v²
4.472135955 = v (Round to whatever the question asks)
v ≈ 4.47 (I rounded to 2 decimal places or 3 significant figures, as that is what it usually is)
Answer:
The speed of the two cars after coupling is 0.46 m/s.
Explanation:
It is given that,
Mass of car 1, m₁ = 15,000 kg
Mass of car 2, m₂ = 50,000 kg
Speed of car 1, u₁ = 2 m/s
Initial speed of car 2, u₂ = 0
Let V is the speed of the two cars after coupling. It is the case of inelastic collision. Applying the conservation of momentum as :
V = 0.46 m/s
So, the speed of the two cars after coupling is 0.46 m/s. Hence, this is the required solution.
Answer:
2.22m/s to the left
Explanation:
Given parameters:
Initial position = +125m
Final position = -75m
Motion time = 90s
Unknown:
Velocity of the steel ball = ?
Solution:
The velocity of the steel ball is given as the displacement divided by the time;
Velocity =
The net displacement of the ball = 125- (-75) = 200m to the left
Input the parameters and solve for the velocity;
Velocity = = 2.22m/s to the left