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Tcecarenko [31]
3 years ago
15

An electron is a negatively charged particle that has a charge of magnitude, e - 1.60 x 10-19 C. Which one of the following stat

ements best describes the electric field at a distance r from the electron? The electric field is directed toward the electron and has a magnitude of ke/r. The electric field is directed away from the electron and has a magnitude of ke/2. The electric field is directed toward the electron and has a magnitude of ke/? The electric field is directed toward the electron and has a magnitude of ke?/r. The electric field is directed away from the electron and has a magnitude of ke/r.
Physics
1 answer:
Ivahew [28]3 years ago
6 0

Answer:

The electric field is directed toward the electron and has a magnitude of E=\frac{ke}{r^{2} }.

Explanation:

An electric field is define as the surrounding of charges which exert a force on each other and this force can be attractive or repulsive depends on the charge.

In the given case electron is given and the magnitude of charge on electron is e=1.6\times 10^{-19}C

Electric field can be represented as,

E=\frac{kQ}{r^{2} }

Here, r is the distance between the point ande charge, k is the electric field constant and Q is the charge.

In the given question an electron is given so electric field will be,

E=\frac{ke}{r^{2} }

As we know that electric field start from the positive charge and vanish in the negative charge.

So, here the electric field will be E=\frac{ke}{r^{2} } and it is directed toward the electron because of negative charge on the electron.

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A red photon has a wavelength of 650 nm. An ultraviolet photon has a wavelength of 250 nm. The energy of an ultraviolet photon i
zimovet [89]

The energy of an ultraviolet photon is 2.6 times greater than a red photon.

<h3>Energy of a photon</h3>

The energy of a given photon of light is calculated using the wavelength and the speed of light.

<h3>Energy of a red photon</h3>

The energy of the a red photon at the given wavelength is calculated as follows;

E_r = \frac{hc}{\lambda} \\\\E_r = \frac{6.67 \times 10^{-34} \times 3 \times 10^8}{650 \times 10^{-9}} \\\\E_r = 3.078 \times 10^{-19} \ J

<h3>Energy of an ultraviolet photon</h3>

E_r = \frac{hc}{\lambda} \\\\E_r = \frac{6.67 \times 10^{-34} \times 3 \times 10^8}{250 \times 10^{-9}} \\\\E_r = 8.0 \times 10^{-19} \ J

<h3>The ratio of the two energies</h3>

= \frac{8.0 \times 10^{-19}}{3.078 \times 10^{-19}} \\\\= 2.6

Thus, the energy of an ultraviolet photon is 2.6 times greater than a red photon.

Learn more about energy of a photon here: brainly.com/question/7464909

4 0
3 years ago
When you cook a steak, what kind of energy do you increase in the steak?
lina2011 [118]

Answer:

B im pretty sure.

Explanation:

4 0
3 years ago
describe an experiment to show how the frequency of a note emitted by a vibrating string depends on the tension of the string
mart [117]
Easy ! 

Take any musical instrument with strings ... a violin, a guitar, etc.

The length of the vibrating part of the strings doesn't change ...
it's the distance from the 'bridge' to the 'nut'.

Pluck any string.  Then, slightly twist the tuning peg for that string,
and pluck the string again.

Twisting the peg only changed the string's tension; the length
couldn't change.

-- If you twisted the peg in the direction that made the string slightly
tighter, then your second pluck had a higher pitch than your first one.

-- If you twisted the peg in the direction that made the string slightly
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3 0
3 years ago
Sayid made a chart listing data of two colliding objects.
Artemon [7]

Answer:

velocity of combined objects is 6 m/s

Explanation:

As per law of conservation of momentum

total momentum before collision = total momentum after collision

since the two objects sticks together after collision so we will have

m_1v_{1i} + m_2v_{2i} = (m_1 + m_2) v

Now plug in all values in it

300(10) + 100(-6) = (300 + 100) v

3000 - 600 = 400(v)

2400 = 400 v

v = 6 m/s

so the missing value in the table is velocity which is 6 m/s

7 0
3 years ago
Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P P and volume V V satisfy th
Verdich [7]

Answer:

the volume decreases at the rate of 500cm³ in 1 min

Explanation:

given

v = 1000cm³, p = 80kPa, Δp/t= 40kPa/min

PV=C

vΔp + pΔv = 0

differentiate with respect to time

v(Δp/t) + p(Δv/t) = 0

(1000cm³)(40kPa/min) + 80kPa(Δv/t) = 0

40000 + 80kPa(Δv/t) = 0

Δv/t = -40000/80

= -500cm³/min

the volume decreases at the rate of 500cm³ in 1 min

3 0
3 years ago
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