Answer:
The volume of CO2 produced is 6.0 L (option D)
Explanation:
Step 1: Data given
Volume of oxygen = 3.0 L
Carbon monoxide = CO = in excess
Step 2: The balanced equation
2 CO (g) + O2 (g) → 2 CO2 (g)
Step 3: Calculate moles of O2
1 mol of gas at STP = 22.4 L
3.0 L = 0.134 moles
Step 3: Calculate moles of CO2
For 2 moles CO we need 1 mol of O2 to produce 2 moles of CO2
For 0.134 moles O2 we'll have 2*0.134 = 0.268 moles CO2
Step 4: Calculate volume of CO2
1 mol = 22.4 L
0.268 mol = 22.4 * 0.268 = 6.0 L
The volume of CO2 produced is 6.0 L
Ok number one is A number 2 is C number 3 is A number 4 is B hope it helps
Answer:
The answer to your question is 150 ml
Explanation:
Data
Volume 1 = 25 ml
Concentration 1 = 0.6 M
Volume 2 = ?
Concentration 2 = 0.1 M
Formula
Volume 1 x Concentration 1 = Volume 2 x Concentration 2
Solve for Volume 2
Volume 2 = (Volume 1 x Concentration 1)/Concentration 2
Substitution
Volume 2 = (25 x 0.6) / 0.1
Simplification
Volume 2 = 15 / 0.1
Result
Volume 2 = 150 ml
Answer:
Top left: RR Top right: Rr Bottom left: Rr Bottom right: rr
Explanation:
if both parents are heterozygous then the table will always look like this. the chances of the offspring being heterozygous are 50%. the offspring has a 25% chance of having two recessive traits and a 25% chance of having two dominant traits.
