Question

(WILL GIVE BRIANLIEST)

Answer 1

Answer:

option (c) $\{-1,\dfrac{4}{3}\}$  is the correct answer.

Step-by-step explanation:

The given Quadratic equation is:

$3x^{2} -x-4=0$

Let us try to make factors:

$3x^{2} -x-4=0$

Here, $-x$ can be written as $-4x + 3x$ (Look at the coefficient of $x^{2}$ and constant part i.e. 3 and 4). So, the quadratic equation becomes:

$\Rightarrow 3x^{2} -4x+3x-4=0\\\text{Taking x common from }3x^{2} -4x \text{ and 1 common from }3x+4:\\\Rightarrow x(3x-4)+1(3x-4)=0\\\Rightarrow (x+1)(3x-4)=0\\\Rightarrow (x+1) =0\ or\ (3x-4) = 0\\\Rightarrow x =-1\ or\ x = \dfrac{4}{3}$

So, solution set for the equation $3x^{2} -x-4=0$ is:

$\{-1,\dfrac{4}{3}\}$

Hence, option (c) $\{-1,\dfrac{4}{3}\}$  is the correct answer.