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RUDIKE [14]
3 years ago
9

Suggest a possible

Chemistry
1 answer:
shepuryov [24]3 years ago
5 0

Answer: a reason for this is fossil fuels

Explanation:

The reduction in SO2 is largely due to the implementation of the Acid Rain Program under the Clean Air Act through a cap and trade program for fossil-fuel powered plants.

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PilotLPTM [1.2K]

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i think A.

Explanation:

bc B. makes the molecules hight temp = move faster = more collisions = higher rate, C. it's use is to make reactions rates increase, D. somthung abt more surface area and easier collisions

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Is there a solution for the impacts overfishing?
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The world’s oceans are so big we thought for a long time that there was nothing humans could do to hurt them. Now we’re facing an imminent and global collapse of our fisheries, projected to happen as early as 2048, thanks to overfishing, wasteful fishing practices and massive overconsumption. But, there are a few key tried-and-tested solutions to overfishing that have been successfully implemented around the world. The trick is to scale these solutions up to a global scale, encouraging countries that have originally been resistant to helping and get them onboard, and supporting countries that don’t have the means to update their fishing policies themselves.

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6 0
3 years ago
Which factors affect both the solubility and rate of dissolution of a solid
klemol [59]
Temperature
Surface area
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6 0
4 years ago
Which salt has a pH &lt; 7? <br> KBr <br> HCOOK <br> CaSO4 <br> NH4NO3
Eva8 [605]
If a salt has a pH less than 7, then it is an acid. All acids start with a H in there formula. The only compound that starts with an H from the listed options is HCOOK.

So the salt HCOOK has a pH<7
5 0
4 years ago
Read 2 more answers
2 HI(g) ⇄ H2(g) + I2(g) Kc = 0.0156 at 400ºC 0.550 moles of HI are placed in a 2.00 L container and the system is allowed to rea
Ivahew [28]

Answer:

The concentration of HI at equilibrium is 0.2445 \frac{moles}{L}

Explanation:

A chemical reaction occurs in both directions: from reagents transforming into products (direct reaction) and from products transforming back into reactants (reverse reaction)

The mathematical expression that  represents the Chemical Balance is the equilibrium constant Kc.

You have:

aA + bB ⇔ cC + dD

where A, B, C and D represent the chemical species involved and a, b, c and d their respective stoichiometric coefficients. So the constant Kc is:

Kc=\frac{[A]^{a}*[B]^{b}  }{[C]^{c}*[D]^{d}  }

That is, this constant Kc is equal to the multiplication of the concentrations of the products raised to their stoichiometric coefficients divided by the multiplication of the concentrations of the reagents also elevated to their stoichiometric coefficients.

So, in this case:

Kc=\frac{[H_{2}]*[I_{2} ] }{[HI]^{2} }=0.0156

You have that the initial concentrations are:

[HI]= \frac{0.550 moles}{2.00 L} = 0.275 \frac{moles}{L}

[H₂]= 0

[I₂]= 0

Being "x" the change in the concentration that occurs during the reaction, which must be affected by the stoichiometric coefficient, the final concentrations of each species in equilibrium will be:

[HI]= 0.275 \frac{moles}{L}-x

[H₂]= x

[I₂]= x

Keep in mind that in the case of reagents the concentration "x" is subtracted because the reagents are consumed. In the case of products, the concentration "x" is added because the reagents are formed.

Then:

0.0156=\frac{x*x}{(0.275-x)^{2} }

Resolving

0.0156*(0.275-x)²=x²

0.0156*(0.075625-0.55*x+x²)=x²

1.17975*10⁻³-8.58*10⁻³*x+0.0156*x²=x²

-0.9844*x²-8.58*10⁻³*x+1.17975*10⁻³=0

Solving for  x  will get you two values: x1≅0.0305 and x2≅-0.0392

Since the value of "x" represents a concentration, and cannot have negative values, the value of x2 is discarded. So: x=x1

Then:

[HI]= 0.275 \frac{moles}{L}-x=0.275 \frac{moles}{L}-0.0305 \frac{moles}{L} = 0.2445 \frac{moles}{L}

[H₂]= 0.0305 \frac{moles}{L}

[I₂]= 0.0305 \frac{moles}{L}

<u><em>The concentration of HI at equilibrium is 0.2445 </em></u>\frac{moles}{L}<u><em></em></u>

4 0
3 years ago
Read 2 more answers
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