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RUDIKE [14]
3 years ago
9

Suggest a possible

Chemistry
1 answer:
shepuryov [24]3 years ago
5 0

Answer: a reason for this is fossil fuels

Explanation:

The reduction in SO2 is largely due to the implementation of the Acid Rain Program under the Clean Air Act through a cap and trade program for fossil-fuel powered plants.

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Most elements occur in nature as a single isotope.<br> TRUE<br> FALSE
cestrela7 [59]

Answer:

false

Explanation:

because elements never exist in nature as single isotopes they are always combined

8 0
3 years ago
Read 2 more answers
Calculate the volume which 1.00 mole of a gas occupies at 1 atm and 298K?
elena-14-01-66 [18.8K]

Answer:

25.45 Liters

Explanation:

Using Ideal Gas Law PV = nRT => V = nRT/P

V = (1mole)(0.08206Latm/molK)(298K)/(1atm) = 25.45 Liters

7 0
3 years ago
Molybdenum (Mo) has a body centered cubic unit cell. The density of Mo is 10.28 g/cm3. Determine (a) the edge length of the unit
ser-zykov [4K]

<u>Answer:</u>

<u>For a:</u> The edge length of the unit cell is 314 pm

<u>For b:</u> The radius of the molybdenum atom is 135.9 pm

<u>Explanation:</u>

  • <u>For a:</u>

To calculate the edge length for given density of metal, we use the equation:

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

\rho = density = 10.28g/cm^3

Z = number of atom in unit cell = 2  (BCC)

M = atomic mass of metal (molybdenum) = 95.94 g/mol

N_{A} = Avogadro's number = 6.022\times 10^{23}

a = edge length of unit cell =?

Putting values in above equation, we get:

10.28=\frac{2\times 95.94}{6.022\times 10^{23}\times (a)^3}\\\\a^3=\frac{2\times 95.94}{6.022\times 10^{23}\times 10.28}=3.099\times 10^{-23}\\\\a=\sqrt[3]{3.099\times 10^{-23}}=3.14\times 10^{-8}cm=314pm

Conversion factor used:  1cm=10^{10}pm  

Hence, the edge length of the unit cell is 314 pm

  • <u>For b:</u>

To calculate the edge length, we use the relation between the radius and edge length for BCC lattice:

R=\frac{\sqrt{3}a}{4}

where,

R = radius of the lattice = ?

a = edge length = 314 pm

Putting values in above equation, we get:

R=\frac{\sqrt{3}\times 314}{4}=135.9pm

Hence, the radius of the molybdenum atom is 135.9 pm

4 0
3 years ago
A gas fills a balloon at a temperature of 27 C and 101.325 kPa of pressure. What will the pressure of the balloon be if the gas
JulijaS [17]

135.1‬kPa

Explanation:

Given parameters:

T1 = 27°C

P1  = 101.325 kPa

T2 = 127°C

Unknown:

P2 = ?

Solution:

Using a derivative of the combined gas law where we assume that the gas has a constant volume, we can solve for the unknown.

 At constant volume:

           \frac{P1}{T1}  = \frac{P2}{T2}

P1 is the initial pressure

T1 is the initial temperature

P2 is the final pressure

T2 is the final temperature

  Take the given temperature to K

T1 = 27 + 273 = 300K

T2 = 127 + 273  = 400K

 Input the variables:

    \frac{101.325}{300}  = \frac{P2}{400}

  P2 = 135.1‬kPa

learn more:

Boyle's law brainly.com/question/8928288

#learnwithBrainly

3 0
3 years ago
Calcium bromide has a formula of CaBr2. Why are there two
tamaranim1 [39]
Bromide gives away 1 electron (valency of 1) and Ca wants to gain 2 electrons (valency of 2) therefore 2 Br ions are needed
6 0
3 years ago
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