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2 years ago

Oak tree

Chemistry

2 answers:

mel-nik [20]2 years ago

4 0

Answer:

The oak tree would have the energy available for use

Murljashka [212]2 years ago

3 0

Oak tree, because it’s the primary producer

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Calculate the mass (in g) of 2.1 x 1024 atoms of W.

Monica [59]

Atomic mass W = 183.84 u.m.a

183.84 g ----------- 6.02x10²⁴ atoms
?? g ---------------- 2.1x10²⁴ atoms

2.1x10²⁴ x 183.84 / 6.02x10²⁴ =

3.860x10²⁶ / 6.02x10²⁴ = 641.30 g

hope this helps!

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3 years ago

Condition required for nuclear fusion in the sun?

Schach [20]

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3 years ago

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A racehorse completes the Kentucky Derby, a distance of 1.25 miles, in

forsale [732]

Answer:

D. 60.3 kilometers per hour

Explanation:

Hello,

In this case, we first compute the miles in kilometres:

$1.25miles*\frac{1.60934km}{1mile} =2.012km$

Then the minutes in hours:

$2.00min*\frac{1h}{60min}=0.033h$

Finally, the velocity:

$v=\frac{2.012km}{0.033h}\\ \\v=60.3km/h$

Thus, answer is D. 60.3 kilometers per hour

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3 years ago

A 2.89 g sample of a metal chloride, MCl2, is dissolved in water and treated with excess aqueous silver nitrate. The silver chlo

dsp73

Answer:

58.0 g/mol

Explanation:

The reaction that takes place is:

MCl₂ + 2AgNO₃ → 2AgCl + M(NO₃)₂

First we calculate how many moles of silver chloride were produced, using its molar mass:

6.41 g AgCl ÷ 143.32 g/mol = 0.0447 mol AgCl

Then we convert AgCl moles into MCl₂ moles, using the stoichiometric ratio:

0.0447 mol AgCl * $\frac{1molMCl_2}{2molAgCl}$ = 0.0224 mol MCl₂

Now we calculate the molar mass of MCl₂, using the original mass of the sample:

2.86 g / 0.0224 mol = 127.68 g/mol

We can write the molar mass of MCl₂ as:

Molar Mass MCl₂ = Molar Mass of M + (Molar Mass of Cl)*2

127.68 g/mol = Molar Mass of M + (35.45 g/mol)*2

Finally we calculate the molar mass of M:

Molar Mass of M = 57 g/mol

The closest option is 58.0 g/mol.

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3 years ago

What observations led to the periodic law? what observations led to the periodic law? observation that certain elements possess

kvv77 [185]

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