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Blababa [14]
3 years ago
6

Longitudinal waves Transverse waves

Physics
2 answers:
Natali [406]3 years ago
5 0

Answer:

longitudinal waves are waves that propagate in the same direction as the direction of movement of ìts particles, for example - sound

whereas

Transverse waves are waves that propagate perpendicular to the direction of movement of its particles, for example- light

galben [10]3 years ago
3 0

Answer:

In a transverse wave, the particles are displayed perpendicular to the direction the wave travels . in a longitudinal wave the particles are are displayed parallel to the direction the wave travels. an example of longitudinal waves in compressions moving along a slinky.

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scoray [572]

Answer:

B and A

Explanation:

6 0
3 years ago
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Water soaks down into the ground in a process known as
astraxan [27]

I think the answer is D

3 0
4 years ago
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Two people, one with mass m1 and the other with mass m2, stand on a stationary sled with mass M on a frozen lake. Assume that th
lozanna [386]

Answer:

Part a)

Velocity of sled

v = \frac{m_1 s}{m_1 + m_2 + M}

velocity of first man who jump off

v_1 = -\frac{(m_2 + M) s}{m_1 + m_2 + M}

Part b)

Velocity of sled

v_f = (\frac{m_1 s}{m_1 + m_2 + M}) + (\frac{m_2}{m_2 + M})s

Also the speed of second person is given as

v_2 = (\frac{m_1 s}{m_1 + m_2 + M}) - \frac{Ms}{m_2 + M}

Part c)

change in kinetic energy of sled + two people is given as

KE = \frac{1}{2}Mv_f^2 + \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2

Explanation:

As we know that here we we consider both people + sled as a system then there is no external force on it

So here we can use momentum conservation

since both people + sled is at rest initially so initial total momentum is zero

now when first people will jump with relative velocity "s" then let say the sled + other people will move off with speed v

so by momentum conservation we have

0 = m_1(v - s) + (m_2 + M)v

v = \frac{m_1 s}{m_1 + m_2 + M}

so velocity of the sled + other person is

v = \frac{m_1 s}{m_1 + m_2 + M}

velocity of first man who jump off

v_1 = \frac{m_1 s}{m_1 + m_2 + M} - s

v_1 = -\frac{(m_2 + M) s}{m_1 + m_2 + M}

Part b)

now when other man also jump off with same relative velocity

so let say the sled is now moving with speed vf

so by momentum conservation we have

(m_2 + M)(\frac{m_1 s}{m_1 + m_2 + M}) = m_2(v_f - s) + Mv_f

(m_2 + M)(\frac{m_1 s}{m_1 + m_2 + M}) + m_2s = (m_2 + M)v_f

Now we have

v_f = (\frac{m_1 s}{m_1 + m_2 + M}) + (\frac{m_2}{m_2 + M})s

Also the speed of second person is given as

v_2 = (\frac{m_1 s}{m_1 + m_2 + M}) + (\frac{m_2}{m_2 + M})s - s

v_2 = (\frac{m_1 s}{m_1 + m_2 + M}) - \frac{Ms}{m_2 + M}

Part c)

change in kinetic energy of sled + two people is given as

KE = \frac{1}{2}Mv_f^2 + \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2

here we know all values of speed as we found it in part a) and part b)

4 0
3 years ago
A closed system contains 30g of gas. How much heat(in joules) is added to or rejected by the system to produce 5000 N-m of work
finlep [7]

Answer : The heat rejected by the system is 1000 J

Explanation :

As per first law of thermodynamic,

q=\Delta U+w

where,

\Delta U = internal energy  of the system

q = heat  added or rejected by the system

w = work done of the system

First we have to determine the internal energy for 30 grams of gas.

As, 1 gram of gas has internal energy = 200 J

So, 30 grams of gas has internal energy = 200 × 30 = 6000 J

Now we have to determine the heat of the system.

q=\Delta U+w

\Delta  = -6000 J

w = 5000 N.m = 5000 J

Now put all the given values in the above formula, we get:

q=-6000J+5000J

q=-1000J

The negative sign indicate that the heat rejected by the system.

Hence, the heat rejected by the system is 1000 J

8 0
3 years ago
In a real isothermal expansion, the temperature of the surroundings must be________the temperature of the gas.
Lady_Fox [76]
Must be isolated from the temperature of the gas
7 0
3 years ago
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