Answer:
0.8 m
Explanation:
Draw a free body diagram. There are three forces:
Weight force mg pulling down,
Normal force N pushing up,
and friction force Nμ pushing towards the center.
Sum of forces in the y direction:
∑F = ma
N − mg = 0
N = mg
Sum of forces in the centripetal direction:
∑F = ma
Nμ = m v²/r
Substitute and simplify:
mgμ = m v²/r
gμ = v²/r
Write v in terms of ω and solve for r:
gμ = ω²r
r = gμ/ω²
Plug in values:
r = (10 m/s²) (0.5) / (2.5 rad/s)²
r = 0.8 m
Answer:
P = 180.81 J
Explanation:
Given that,
Mass of a object, m = 4.1 kg
It is lifted to a height of 4.5 m
We need to find the potential energy of the object due to gravity. It is given by the formula as follows :
P = mgh Where g is acceleration due to gravity
P = 4.1 kg × 9.8 m/s² × 4.5 m
P = 180.81 J
Hence, the potential energy is 180.81 J.
<h2>What is an electric fuse?</h2><h3>
Answer: Electric fuse is a safety device used to limit the current in an electric circuit which melts and breaks the circuit whenever there is an excess flow of current through the circuit.</h3><h2>What is the working principle of electric fuse?</h2><h3>An electric fuse is based on the principle of heating effect of electric current. It is made up of thin metallic wire of non-combustible material. A fuse is always connected between the ends of the terminal in a series connection with the circuit.</h3>
Answer:
here on the surface of moon the gravity decreases so the frequency of oscillation will also decrease
Explanation:
As we know that frequency of oscillation of the simple pendulum is given as
here we know
g = acceleration due to gravity at the surface of the planet
L = length of the pendulum
Now we know that the pendulum is on the surface of earth then gravity is given as
now when same pendulum is taken to the surface of the moon then we have
so here on the surface of moon the gravity decreases so the frequency of oscillation will also decrease
