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lozanna [386]
3 years ago
10

A 69 kg driver gets into an empty taptap to start the day's work. The springs compress 2×10−2 m . What is the effective spring c

onstant of the spring system in the taptap? Enter the spring constant numerically in newtons per meter using two significant figures.
Physics
1 answer:
natulia [17]3 years ago
3 0

Answer:

3.4\cdot 10^4 N/m

Explanation:

The spring system in the taptap obey's Hooke's law, which states that:

F=kx

where

F is the magnitude of the force applied

k is the spring constant

x is the compression/stretching of the spring

In this problem:

- The force applied is the weight of the driver of mass m = 69 kg, so

F=mg=(69 kg)(9.8 m/s^2)=676.2 N

- The compression of the spring is

x=2\cdot 10^{-2} m=0.02 m

So, the spring constant is

k=\frac{F}{x}=\frac{676.2 N}{0.02 m}=3.4\cdot 10^4 N/m

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