Solution :
We know,
Distance,
For the first 20 ms,
S = 0.044 m
In the remaining 30 ms, it has constant velocity.
v = 4.4 m/s
Therefore,
S' = 0.132 m
So, the required distance is = S + S'
= 0.044 + 0.132
= 0.176 m
Therefore, the tongue can reach = 0.176 m or 17.6 cm
Answer:
0.14 kg
Explanation:
a= (Vf²- Vi²)/2.d
the final velocity is 0 (rest), and the initial velocity is 92 mi/h, that is equal to 41 m/s and the distance is 0.15 meters.
a= -5603 m/s² the minos means that the object is decelerating.
then we can use the second Newton law
F= m.a
m= F/a -----> m= 803N / 5603 m/s²
m= 0.14 kg