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3 years ago

How do you convert 1.3*10^6cal into joules

Physics

1 answer:

ehidna [41]3 years ago

3 0

Answer:

5.4×10⁶J

Explanation:

1 cal = 4.184 J

1.3×10⁶ cal × (4.184 J/cal) = 5.4×10⁶J

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Use this table of a school bus during morning pickups to calculate its average speed between 0 h and 2.340 h.

Gelneren [198K]

The average speed between 0 h and 2.340 h is 6.97 Km/h

Average speed is defined as the total distance travelled divided by the total time taken to cover the distance.

$Average \: speed = \frac{total \: distance}{total \: time} \\ \\$

With the above formula, we can obtain the average speed between 0 h and 2.340 h as illustrated below:

Total time = 2.340 – 0 = 2.340 h
Total distance = 16.3 – 0 = 16.3 Km
Average speed =?

$Average \: speed = \frac{total \: distance}{total \: time} \\ \\Average \: speed = \frac{16.3}{2.340} \\ \\ Average \: speed = 6.97 \: Km/h \\ \\$

Learn more about average speed: brainly.com/question/24884027

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2 years ago

I don't know the answer to 1

larisa86 [58]

Waves transfer energy but not matter

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4 years ago

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A uniform conducting rod of length 34 cm has a potential difference across its ends equal to 39 mV (millivolts). What is the mag

lozanna [386]

Electric field is the change in voltage per unit distance

E = ΔV / d

E = 39/34

= 1/147 mV/cm

hope this helps

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4 years ago

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The immersed volume of body in a liquid depends on density of the liquid. TRUE or FALSE?

miss Akunina [59]

Answer:

True - Archimedes Principle states that the buoyant force on an object is equal to the weight of the liquid displaced.

8 0

2 years ago

The vertical motion of mass A is defined by the relation x 5 10 sin 2t 1 15 cos 2t 1 100, where x and t are expressed in millime

nikklg [1K]

Explanation:

Given that,

The vertical motion of mass A is defined by the relation as :

$x=10\ sin2t+15\ cos2t+100$

At t = 1 s

$x=10\ sin2+15\ cos2+100$

x = 115.33 mm

(a) We know that,

Velocity, $v=\dfrac{dx}{dt}$

$v=\dfrac{d(10\ sin2t+15\ cos2t+100)}{dt}$

$v=20\ cos2t-30\ sin2t$

At t = 1 s

$v=20\ cos2-30\ sin2$

v = 18.94 mm/s

We know that,

Acceleration, $a=\dfrac{dv}{dt}$

$a=\dfrac{d(20\ cos2-30\ sin2)}{dt}$

$a=-40\ cos2t-60\ cos2t$

At t = 1 s

$v=-40\ cos2-60\ cos2$

$a=-99.93\ mm/s^2$

(b) For maximum velocity, $\dfrac{dv}{dt}=a=0$

$-40\ cos2t-60\ cos2t=0$

t = 45 seconds

For maximum acceleration, $\dfrac{da}{dt}=0$

$80\ sin2t+120\ cos2t=0$

t = 61.8 seconds

Hence, this is the required solution.

5 0

4 years ago