The first one is -4 and the second one is 6.
Answer: 3x^+13x-56
Steps
1). Multiply the parentheses
(X+7)(3x-8)
=X x 3x -8x+7 x 3x -7 x 8
2). Multiply
3x^-8x + 21x - 56
3). Do like terms
3x^+13x - 56
4). Solution
[3x^+13x - 56]
-HOPE THAT HELPEDED <3
Hi! I'm pretty sure this is correct so here it goes:
A. 3/6
B. 12 4/6
Answer:
f³(x) = 64/x⁶
Step-by-step explanation:
f³(x) = (f(x))³ = (4/x²)³ = 4³/(x²)³
f³(x) = 64/x⁶
_____
The applicable rules of exponents are ...
(a/b)^c = (a^c)/(b^c)
(a^b)^c = a^(bc)
Answer:
a) The mean number of cases is 0.14608 cases.
b) The probability that the number of cases is exactly 0 or 1 is 0.990.
c) The probability of more than one case is 0.010
d) No, because the probability of more than one case is very small
Step-by-step explanation:
We can model this problem with a Poisson distribution, with parameter:

a) The mean amount of cases is equal to the parameter λ=0.14608.
b) The probability of having 0 or 1 cases is:

c) The probability of more than one case is:

d) The cluster of 4 cases can not be due to pure chance, as it is a very high proportion of cases according to the average rate. Just having more than one case has a probability of 1%.