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3 years ago

Come up with 2 examples of each law motion below: 1st law: 2nd law: 3rd law:

1 answer:

5 0

1st law: Inertia, If you roll a ball it will not stop unless something blocks it by force.

2nd law: Force and Acceleration, when you’re riding a bike you are pushing the pedal with ur muscle which means you’re using force. Everytime you push the pedal the bike goes faster and faster which explains acceleration.

3rd law: Action and Reaction, If you run you’re feet pushes the ground (action) when your feet touches the ground it pushes you forward (reaction)

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The rate of disappearance of HBr in the gas phase reaction2HBr(g) → H2(g) + Br2(g)is 0.301 M s-1 at 150°C. The rate of appearanc

jok3333 [9.3K]

Answer: 0.151

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$2HBr(g)\rightarrow H_2(g)+Br_2(g$

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

$Rate=-\frac{1d[HBr]}{2dt}=+\frac{1d[H_2]}{2dt}=+\frac{1d[Br_2]}{dt}$

Given: $-\frac{d[HBr]}{dt}]=0.301$

Putting in the values we get:

$\frac{0.301}{2}=+\frac{1d[Br_2]}{dt}$

$+\frac{1d[Br_2]}{dt}=0.151$

Thus the rate of appearance of $Br_2$ is 0.151

8 0

3 years ago

When hydrogen chloride (HCI) reacts with ammonia (NH3), ammonium chloride (NH4CI) is

givi [52]

Answer:

AMEN NNNNNNNNNNNNNNNNNNNNNNNN

6 0

3 years ago

Let's assume you were given 2.0 g benzil, 2.2 g dibenzyl ketone, 50 mL 95% ethanol and 0.3 g potassium hydroxide to synthesize t

almond37 [142]

Answer:

the % yield is 82%

Explanation:

Given the data in the question,

we know that;

Molar mass of benzil is 210.23 g·mol−1

Molar mass of dibenzyl ketone is 210.27 g·mol−1

Molar mass of tetraphenylcyclopentadienone is 384.5 g·mol−1

Now,

2.0 g benzil = 2 g / 210.23 g·mol−1 = 0.0095 mole

2.2 g dibenzyl ketone = 2.2 / 210.27 = 0.0105 mole

3.0 g of tetraphenylcyclopentadienone = 3 / 384.5 = 0.0078 mole

Now, the limiting reagent is benzil. 0.0095 mole can reacts wiyh 0.0095 mole of dibenzyl ketone

percentage yield = ( 0.0078 mole / 0.0095 mole ) × 100%

= 0.82 × 100%

= 82%

Therefore, the % yield is 82%

3 0

3 years ago

Percent composition of Mg(OH)2

LuckyWell [14K]

Answer:

The composition of Mg(OH)2 is

41.67 % Mg,

54.87 % O

3.457 % H

Explanation:

Thats the percent composition for each one in your question

4 0

2 years ago

Read 2 more answers

What action could slow a chemical reaction rate?

Free_Kalibri [48]

The action that could slow a chemical reaction rate is adding more of a substance to a mixture. The answer is letter d. It does not give time for the rest of the reactants to be consumed because you are adding more of it causing to slow the reaction.

6 0

3 years ago