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zhannawk [14.2K]
2 years ago
13

Come up with 2 examples of each law motion below: 1st law: 2nd law: 3rd law:

Chemistry
1 answer:
Sloan [31]2 years ago
5 0
1st law: Inertia, If you roll a ball it will not stop unless something blocks it by force.

2nd law: Force and Acceleration, when you’re riding a bike you are pushing the pedal with ur muscle which means you’re using force. Everytime you push the pedal the bike goes faster and faster which explains acceleration.

3rd law: Action and Reaction, If you run you’re feet pushes the ground (action) when your feet touches the ground it pushes you forward (reaction)
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Using the Brønsted-Lowry concept of acids and bases, identify the Brønsted-Lowry acid and base in each of the following reaction
Luden [163]

Answer:

1. HSO³⁻(aq) + H₂O(l) → H₂SO₃(aq) + OH⁻(aq)

<u>The Brønsted-Lowry acid is H₂O and the Brønsted-Lowry base is HSO³⁻</u>

<u />

2. (CH₃)₃N(g) + BCl₃(g) → (CH₃)₃NBCl₃(s)

<u>There are no Brønsted-Lowry acids and bases in this reaction.</u>

Explanation:

According to the Brønsted-Lowry concept, when an acid (HA) and a base (B) undergoes a chemical reaction, the acid (HA) loses a proton and forms its conjugate base (A⁻), whereas the base gains (B) the proton to form its conjugate acid (HB⁺).

<em>The chemical equation for this reaction is:</em>

HA  +  B  ⇌  A⁻  +  HB⁺

Given reactions:

1. HSO³⁻(aq) + H₂O(l) → H₂SO₃(aq) + OH⁻(aq)

<u>The Brønsted-Lowry acid is H₂O and the Brønsted-Lowry base is HSO³⁻</u>

Reason: In this reaction, the acid H₂O loses a proton and forms its conjugate base, OH⁻. Whereas, the base HSO³⁻ gains a proton to form its conjugate acid, H₂SO₃.

2. (CH₃)₃N(g) + BCl₃(g) → (CH₃)₃NBCl₃(s)

<u>There are no Brønsted-Lowry acids and bases in this reaction.</u>

Reason: In this reaction, there is no exchange of proton between the acid and the base.

4 0
3 years ago
What metal will have properties most similar to those of chromium (Cr)? Why?
garri49 [273]
That element is manganese. As they are in same horizontal row (period) and are next to each other. That is why they show same properties. 

Hope this helps xox :)
5 0
3 years ago
Geologists may choose to lick a mineral to identify it. What mineral is the geologist expecting with this test?
Archy [21]
<span>NaCl (halite) or KCl (sylvite) </span>
8 0
3 years ago
The gravitational force exerted by an object is given by F = mg, where F is the force in newtons, m is the mass in kilograms, an
Andre45 [30]

The height of the column is 0.457 m and the mass of the atmosphere is calculated as 1.03 × 10 ⁴ kg.

<h3>What is Pascal? </h3>

Pascal is defined as the force per unit area. It expressed in Newton pr square meter of area.

1 Pa = 1 N / m²

Pressure = force / Area

According to the question, the expression of force is as given below

F = mg

where,

F is the force,

m is the mass,

g is equal to the acceleration due to the gravity

Now, the area of the atmosphere is 1 m².The pressure is 1 atm. Pressure in Pascal.

1 atm = 1.01325 × 10 5pa

Therefore, the expression for pascal become as follows.

1.01325 × 10 5 pa = mg /area

1.01325 × 10 5 pa = m × 9.81 m/s² / 1 m²

M = 1.01325 × 10 5 pa × 1 m² / 9.81 m² × 1 Nm -² /1 pa × 1 kg m-² / 1 N

1.03 × 10 ⁴ kg

Given,

The density is 22.6 g /mL , pressure is 1 atm, and area is 1 m²

The relation between density and pressure can be given as follows.

P = hpg… … …(1 )

were , h is the height of the column

p is the density.

Hpg = 1.01325 × 10 5 pa × 1 N/m² /1 pa

H = 1.01325 × 10 5 N/m² / pg × 1 kg ms-² / 1 N

= 1.01325 × 10 5 kg m-¹ s -² / 22.6 g mL -1 × 1 kg/ 10 ³ g × 1 mL / 10 -6 m ³ × 9.81 m s- ²

= 0.457 m

Therefore, the height of the column is 0.457 m.

Thus, we concluded that the height of the column is 0.457 m and the mass of the atmosphere is calculated as 1.03 × 10 ⁴ kg.

learn more about density:

brainly.com/question/952755

#SPJ4

7 0
2 years ago
Analyze your results.
raketka [301]

#b

According to Le C ha.te llors principle of we increase concentration of reactants or products equilibrium shifts.

  • Yes increases

#c

  • Rate of reaction also increases

#e

Stated in b

3 0
2 years ago
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