Answer:
25.6g de HF son producidos
Explanation:
<em>...¿Cuánto HF es producido?</em>
Para resolver este problema debemos convertir la masa de cada reactivo a moles usando su masa molar. Como la reacción es 1:1, el reactivo con menor número de moles es el reactivo limitante. Con las moles del reactivo limitante podemos obtener las moles de HF y su masa así:
<em>Moles CaF2:</em>
Masa molar:
1Ca = 40g/mol
2F = 19*2 = 38g/mol
40+38 = 78g/mol
50g CaF2 * (1mol/78g) = 0.641 moles CaF2
<em>Moles H2SO4:</em>
Masa molar:
2H = 2g/mol
1S = 32g/mol
4O = 64g/mol
98g/mol
100g H2SO4 * (1mol / 98g) = 1.02 moles H2SO4
Como las moles de CaF2 < Moles H2SO4: CaF2 es reactivo limitante.
<em>Moles HF usando la reacción:</em>
0.641 moles CaF2 * (2mol HF / 1mol CaF2) = 1.282 moles HF
<em>Masa HF:</em>
Masa molar:
1g/mol + 19g/mol = 20g/mol
1.282 moles HF * (20g/mol) =
<h3>25.6g de HF son producidos</h3>
Aluminum foil I think but if not goodluck :)
Answer:
Explanation:
= First mass of water = 12 oz
= Second mass of water = 20 oz
= Temperature difference of the solution with respect to the first mass of water = 
= Temperature difference of the solution with respect to the second mass of water =
c = Specific heat of water
As heat gain and loss in the system is equal we have
The final temperature of the solution is .
N₂H₄ :
N = - 2
H = + 1
2 * ( -2 ) + ( 1 * 4 ) = - 4 + 4 = 0
hope this helps!
A
single oxygen has atomic number 8 that means the nuclei of all oxygen atoms
have eight protons. The number of minus-charged electron is two but the number
of electrons is 10. <span>To gain a minus two-charge ion, it
must have two more negative electrons than positive charged protons. With this,
the ion has 10 electrons, which give it a -2 net charge. </span>
