Discrete data is numerical but only has a limited number of values.
In this case, the number of rides in an amusement park would be discrete because you cannot have, for example, 5.6 rides.
The correct answer is A.
Just add all 3 numbers up together:
6.45+ 0.15+0.5
=7.1
Since it was three days multiply the 7.1 by three
=7.1x3
=24
So for three days derrick rode for 24 km
Hoped I helped :)
30 minutes = 34. 60 minutes=68
Answer:
The 95% confidence interval for μ for the given situation is between 87.49 and 94.51.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
![\alpha = \frac{1-0.95}{2} = 0.025](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B1-0.95%7D%7B2%7D%20%3D%200.025)
Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so ![z = 1.96](https://tex.z-dn.net/?f=z%20%3D%201.96)
Now, find the margin of error M as such
![M = z*\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%2A%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
In which
is the standard deviation of the population and n is the size of the sample.
![M = 1.96\frac{20}{\sqrt{125}} = 3.51](https://tex.z-dn.net/?f=M%20%3D%201.96%5Cfrac%7B20%7D%7B%5Csqrt%7B125%7D%7D%20%3D%203.51)
The lower end of the interval is the sample mean subtracted by M. So it is 91 - 3.51 = 87.49
The upper end of the interval is the sample mean added to M. So it is 91 + 3.51 = 94.51
The 95% confidence interval for μ for the given situation is between 87.49 and 94.51.
I believe the answer would be 120