Answer:
Mass of hydrogen produced =2.28 g
Explanation:
Given data:
Mass of tin = 67.3 g
Mass of hydrogen produced = ?
Solution:
Chemical equation:
Sn + 2H₂O → SnO₂+ 2H₂
Number of moles of Sn:
Number of moles = mass/ molar mass
Number of moles = 67.3 g/ 118.71 g/mol
Number of moles = 0.57 mol
Now we will compare the moles of tin with hydrogen from balance chemical equation.
Sn : H₂
1 : 2
0.57 : 2×0.57 = 1.14
Mass of hydrogen:
Mass = number of moles ×molar mass
Mass = 1.14 mol × 2 g/mol
Mass = 2.28 g
Answer: 
Explanation:
First we have to calculate the heat absorbed by bomb calorimeter
Formula used :

= heat absorbed by calorimeter = ?
= specific heat of = 10.69 kJ/K
= final temperature = 
= initial temperature = 

As heat absorbed by calorimeter is equal to the heat released by acetylene during combustion.
Thus 1.53 gram of acetylene releases heat of combustion = 258.7kJ
So, 26.04 g/mole of acetylene releases heat of combustion 
Therefore, the heat of combustion of acetylene is, 