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Hoochie [10]
2 years ago
11

convert 0.876 atm to mmHg. solution: multiply the atm value by 760.0 mmHg/ 1.0 atm 0875 atm x _______ = _______ mm Hg (3 sig fig

s)
Chemistry
1 answer:
Akimi4 [234]2 years ago
5 0

\tt \dfrac{760~mmHg}{1~atm}\times 0.876~atm=665~mmHg

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Of the choices below, which is the most abundant gas in Earth's atmosphere?
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B. Nitrogen

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Imagine you are and astronaut returning to Earth from a space mission to Mars. In which order would you pass through the layers
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What mass of hydrogen will be produced by the reaction of 67.3 g of tin with excess water according to the following reaction?
Crank

Answer:

Mass of hydrogen produced =2.28 g

Explanation:

Given data:

Mass of tin = 67.3 g

Mass of hydrogen produced = ?

Solution:

Chemical equation:

Sn + 2H₂O    → SnO₂+ 2H₂

Number of moles of Sn:

Number of moles = mass/ molar mass

Number of moles = 67.3 g/ 118.71 g/mol

Number of moles = 0.57 mol

Now we will compare the moles of tin with hydrogen from balance chemical equation.

                             Sn             :               H₂

                              1               :                2

                          0.57             :               2×0.57 = 1.14

Mass of hydrogen:

Mass = number of moles ×molar mass

Mass = 1.14 mol × 2 g/mol

Mass = 2.28 g

6 0
3 years ago
Oxyacetylene torches produce such high temperature that they are often used to weld and cut metal. When 1.53 g of acetylene (C2H
hodyreva [135]

Answer: 4403kJ/mole

Explanation:

First we have to calculate the heat absorbed by bomb calorimeter  

Formula used :

q_b=c_b\times (T_{final}-T_{initial})

q_b = heat absorbed by calorimeter = ?

c_b = specific heat of = 10.69 kJ/K

T_{final} = final temperature = 44.688^oC=(273+44.688)K=317.688K

T_{initial} = initial temperature = 20.486^oC=(273+20.486)K=293.486K

q_b=10.69kJ/K\times (317.688-293.486)=258.7kJ

As heat absorbed by calorimeter is equal to the heat released by acetylene during combustion.

Thus 1.53 gram of acetylene releases heat of combustion = 258.7kJ

So, 26.04 g/mole of acetylene releases heat of combustion \frac{258.7}{1.53}\times 26.04=4403kJ/mole

Therefore, the heat of combustion of acetylene is, 4403kJ/mole

7 0
4 years ago
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