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3 years ago

An unknown compound has the following chemical formula:

Chemistry

1 answer:

Softa [21]3 years ago

5 0

Answer:

Formula of the compound = $P_2O_5$

Explanation:

Given,

No. of mole of O = 8.20 mol

No. of mole of P = 3.30 mol

Chemical formula = $P_2O_x$

Ratio of P and O = $\frac{2}{x}$

$\frac{2}{x} =\frac{3.3}{8.20} \\x \times 3.3 = 8.20 \times 2\\x = \frac{8.20 \times 2}{3.3} \\x=4.9969\\ = 5$

formula of the compound = $P_2O_5$

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Solve for a, b, c, AND d d C 84° 930 970 b

olga55 [171]

Answer:

a = 87

b = 83

c = 96

d = 86

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3 years ago

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Explain in words or using your diagrams how beryllium atoms would react with fluorine atoms.

Marysya12 [62]

Explanation:

To delineate the the nature of the bonds that would be formed between the two elements, let us first write the electronic configuration of the two species;

Be = 2, 2

F = 2, 7

Beryllium is a metal with two valence electrons whereas fluorine is a halogen with seven valence electrons.

When Be loses two electrons it becomes isoelectronic with He;

Be → Be²⁺ + 2e⁻

Also, when fluorine gains an electron, it becomes isoelectronic with Ne;

F + e⁻ → F⁻

This loss and gain of electrons between the two elements creates an electrostatic attraction them and they enter into an electrovalent bond.

Hence;

Be²⁺ + 2F⁻ → BeF₂

8 0

2 years ago

28.7 l of propane, c3h8, are consumed in a combustion reaction. how many grams of water are produced?

lora16 [44]

The chemical reaction would be:

C3H8 + 5O2 = 3CO2 + 4H2O

For this case, we assume that gas is ideal thus in every 1 mol the volume would be 22.41 L. We calculate as follows:

28.7 L C3H8 ( 1 mol / 22.41 L ) ( 4 mol H2O / 1 mol C3H8 ) ( 18.02 g / mol ) = 92.31 g H2O produced

Hope this answers the question.

7 0

3 years ago

Problem page in each of the molecules drawn below one chemical bond is colored red. decide whether this bond is likely to be pol

Slav-nsk [51]

The question is incomplete, here is the complete question:

Problem page in each of the molecules drawn below one chemical bond is colored red. Decide whether this bond is likely to be polar or not. if the bond is likely to be polar, write down the chemical symbol for the atom which will have more negative charge.

The image is attached below.

Answer:

For carbon dioxide molecule: The bond is considered as polar and the elecvtronegative atom is oxygen.

For water molecule: The bond is considered as polar and the elecvtronegative atom is oxygen.

Explanation:

There are two types of covalent bonds:

Polar covalent bond: This bond is formed when difference in electronegativity between the atoms is present. When atoms of different elements combine, it results in the formation of polar covalent bond. For Example: $CO_2,NO_2$ etc..
Non-polar covalent bond: This bond is formed when there is no difference in electronegativity between the atoms. When atoms of the same element combine, it results in the formation of non-polar covalent bond. For Example: $N_2,O_2$ etc..

In carbon dioxide molecule:

The given bond is present between C and O atom.

Electronegativity value of C = 2.5

Electronegativity value of O = 3.5

Electronegativity difference = (3.5 - 2.5) = 1

As, electronegativity difference is present. So, the bond is considered as polar and the elecvtronegative atom is oxygen.

In water molecule:

The given bond is present between H and O atom.

Electronegativity value of H = 2.1

Electronegativity value of O = 3.5

Electronegativity difference = (3.5 - 2.1) = 1.4

As, electronegativity difference is present. So, the bond is considered as polar and the elecvtronegative atom is oxygen.

8 0

3 years ago

When an aluminum cube of edge 0.100 m and temperature T0= 5.00°C is submerged in a bucket of water, the level of the water rises

vodka [1.7K]

Answer:

5.52cm³ of water will rise and might spill over the edge

Explanation:

Use the change in volume of a liquid with changing temperature equation which is written as

ΔV = β x V₀ x ΔT, where β is the coefficient of expansion, V₀ is the volume being submerged and ΔT is the difference in temperature

ΔV = (69 x 10⁻⁶) x (0.1 x 0.1 x 0.1) x (85 - 5)

ΔV = 5.52 x 10⁻⁶ m³

ΔV = 5.52cm³

7 0

3 years ago