The distance traveled by the ball before hitting the ground is 7.2 m.
The given parameters:
- Angle of projection, θ = 37⁰
- Horizontal velocity, V = 20 m/s
- Height above the ground, h = 1 m
<h3>Vertical motion of a projectile;</h3>
- The vertical motion of a projectile is affected by gravity.
The time of motion of the ball is calculated as follows;
The horizontal distance traveled by the ball before hitting the ground is calculated as follows;
Thus, the distance traveled by the ball before hitting the ground is 7.2 m.
Learn more about horizontal distance here: brainly.com/question/24784992
Answer:
Hey ! I think I can help with this question.
In the diagram you were given the speed which is 5.25m/s and you were also given distance which is 950metres.
So the formula which will be suitable in my own way will be speed=distance/time....Since you weren't given the time,then you can place the numbers in their respectively places which will be 5.25=950/time....Then you will cross multiply which will be 5.25t=950....Then 950÷5.25=180.952381 which is approximately 181. then don't forget to add your unit, time is measured in seconds so the answer is going to be 181seconds.This is what I know...I hope this helps you.....Thank you for the question
Answer:
The velocities of each ball are
Explanation:
Using the conservation of momentum to find the velocity of each balls after the collision
Here have one equation but have two variable don't know so
Now have two equations and two variables so solving using
<span>movement of energy through space or a medium Hope this works! ;3</span>