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Mrrafil [7]
3 years ago
9

Pls help with all questions dew in 10 minutes!

Physics
1 answer:
Artyom0805 [142]3 years ago
5 0
7.Jupiter is the largest planet in our solar system at nearly 11 times the size of Earth and 317 times its mass.

When we look at Jupiter, we're actually seeing the outermost layer of its clouds.

The Great Red Spot is a storm in Jupiter's southern hemisphere with crimson-colored clouds that spin counterclockwise at wind speeds

8. 58,232 km

The second largest planet in the solar system

Surface. As a gas giant, Saturn doesn't have a true surface. The planet is mostly swirling gases and liquids deeper down.

Saturn's rings are thought to be pieces of comets, asteroids or shattered moons that broke up before they reached the planet,

9. Unlike the other planets of the solar system, Uranus is tilted so far that it essentially orbits the sun on its side, with the axis of its spin nearly pointing at the star.

Uranus' atmosphere is mostly hydrogen and helium, with a small amount of methane and traces of water and ammonia.

As an ice giant, Uranus doesn't have a true surface. The planet is mostly swirling fluids. While a spacecraft would have nowhere to land on Uranus, it wouldn't be able to fly through its atmosphere unscathed either. The extreme pressures and temperatures would destroy a metal spacecraft.

10. 24,622 km

Neptune has an average temperature of -353 Fahrenheit (-214 Celsius).

Neptune's atmosphere is made up mostly of hydrogen and helium with just a little bit of methane.

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When designing an experiment, the first step is to ____.
Juliette [100K]
The choices for this question can be found elsewhere and as follows:

<span>(a) state a hypothesis
(b) list a procedure
(c) state the problem
(d) analyze the data

I think the correct answer from the choices listed is option C. </span><span>When designing an experiment, the first step is to state the problem because you cannot proceed to other parts without knowing the problem.</span>
3 0
3 years ago
A person can run 400m in 72 s.. At what speed are they running
rewona [7]
Speed = distance/time
= 400/72
=5.55 m/s
6 0
3 years ago
What tool is used to determine the mass of an object?
melisa1 [442]
A Beam balance (or Beam scale) is a device to measure weight or mass. These are also known as mass scales, weight scales, mass balances, weight balances, or simply scales, balances, or balance scales. You can also use a graduated cylinder and determine the water displaced and figure out the mass of an object this way!

- if this answer is what you were looking for, don’t forget to heart and maybe if you really liked it brainliest :)
3 0
3 years ago
Two charges, each of 2.9 microC are placed at two corners of a square 50cm on a side, If the charges are on one side of the squa
anyanavicka [17]

Answer:

The magnitude of the electric field and direction of electric field are 146.03\times10^{3}\ N/C and 75.36°.

Explanation:

Given that,

First charge q_{1}= 2.9\mu C

Second chargeq_{2}= 2.9\mu C

Distance between two corners r= 50 cm

We need to calculate the electric field due to other charges at one corner

For E₁

Using formula of electric field

E_{1}=\dfrac{kq}{r'^2}

Put the value into the formula

E_{1}=\dfrac{9\times10^{9}\times2.9\times10^{-6}}{(50\sqrt{2}\times10^{-2})^2}

E_{1}=52200=52.2\times10^{3}\ N/C

For E₂,

Using formula of electric field

E_{1}=\dfrac{kq}{r^2}

Put the value into the formula

E_{2}=\dfrac{9\times10^{9}\times2.9\times10^{-6}}{(50\times10^{-2})^2}

E_{2}=104400=104.4\times10^{3}\ N/C

We need to calculate the horizontal electric field

E_{x}=E_{1}\cos\theta

E_{x}=52.2\times10^{3}\times\cos45

E_{x}=36910.97=36.9\times10^{3}\ N/C

We need to calculate the vertical electric field

E_{y}=E_{2}+E_{1}\sin\theta

E_{y}=104.4\times10^{3}+52.2\times10^{3}\sin45

E_{y}=141310.97=141.3\times10^{3}\ N/C

We need to calculate the net electric field

E_{net}=\sqrt{E_{x}^2+E_{y}^2}

Put the value into the formula

E_{net}=\sqrt{(36.9\times10^{3})^2+(141.3\times10^{3})^2}

E_{net}=146038.69\ N/C

E_{net}=146.03\times10^{3}\ N/C

We need to calculate the direction of electric field

Using formula of direction

\tan\theta=\dfrac{141.3\times10^{3}}{36.9\times10^{3}}

\theta=\tan^{-1}(\dfrac{141.3\times10^{3}}{36.9\times10^{3}})

\theta=75.36^{\circ}

Hence, The magnitude of the electric field and direction of electric field are 146.03\times10^{3}\ N/C and 75.36°.

4 0
3 years ago
The lung capacity of the average adult is 5.5 liters at the surface and only .37 liters at a depth of 100 meters. The formula to
Alika [10]
I think you can just sub the values in? unless the qn is asking for smth else?

4 0
3 years ago
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