Answer:
Explanation:
Work done by torque is given as
Word one = torque × angular displacement
W = τ × θ
Given that,
τ = 2000Nm
Mass of motor = 300kg
Radius r = 55cm = 0.55m
Work done by wheel in first t= 23second.
Now we need to find the angular displacement
We know that,
τ = I•α
Moment of inertia of wheel
I = MR²
I = 300 × 0.55²
I = 90.75 kgm²
Then, τ = I•α
α = τ / I
α = 2000/90.75
α = 22.04rad/s²
Then, using circular motion,
∆θ = wit + ½αt²
wi = 0rad/s
∆θ = ½αt²
∆θ = ½ × 22.04 × 23²
∆θ = 5829.2 rad.
Then,
Work done?
W = τ × θ
W = 2000 × 5829.2
W = 1.17 × 10 ^7 J
Answer:
6.25 A
Explanation:
We cant find the current drawn by the element by using Ohm's law:
![V=RI](https://tex.z-dn.net/?f=V%3DRI)
where
V is the potential difference across the resistance of the element
R is the resistance
I is the current
In this problem, we know
V = 200 V
![R=32.0 \Omega](https://tex.z-dn.net/?f=R%3D32.0%20%5COmega)
Therefore we can re-arrange the equation and solve for the current:
![I=\frac{V}{R}=\frac{200}{32}=6.25 A](https://tex.z-dn.net/?f=I%3D%5Cfrac%7BV%7D%7BR%7D%3D%5Cfrac%7B200%7D%7B32%7D%3D6.25%20A)
V2 = 4.4579 L
Since pressure is constant, use Charle’s law.
Charles's law, a statement that the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature, if the pressure remains constant.
V(olume) 1 = V(olume) 2
————— —————
T(emperature) 1 T(emperature)2
4.00 L = V2
———- ———
297 K 331 K
Cross multiply
(4.00 L x 331 K) = (297 K x V2)
Simplify
1324 L/K = 297 K x V2
Isolate V2 by dividing out 297 K
1324 L/K = V2
————
297 K
(This cancels out the kelvin and leaves you with Liters as the volume measure)
V2 = 4.4579 L
Round to significant digits if required
E) No. Ollie will shine for 30 Billion years but is only 10,000 LY from Earth.
F) No. Cosmo will shine for 3 Million years but is 10 Billion LY from Earth.
G) Yes. Ollie is only 10.000 LY away but will shine for 30 Billion years.
Ga) No. Stars such as Cosmo shine for 3 Million years.
Gb) If Cosmo was also 3 Million LY away we would see it now.