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3 years ago

13

A football player kicks a ball with an initial velocity of 25 m/s at an angle of 53 degrees above the horizontal. The vertical c

omponent of the initial velocity of the ball

1 answer:

Verdich [7]3 years ago

7 0

Answer:

20 m/s

Explanation:

initial velocity, u= 25m/s

u has two components. one in horizontal and in one vertical.

so,

u sin theta = vertical component.

=> u sin theta = 25× 4/5

= 20 m/s

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Modern observations have shown that the geometry of the universe is ____.

lesantik [10]

Modern observations have shown that the geometry of the universe is flat and the universe mist be infinite.

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Geometry refer to a branch of mathematics that encapsulates measurements of lines, shapes, dimensions, points and shapes.

Therefore, Modern observations have shown that the geometry of the universe is flat and the universe mist be infinite.

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2 years ago

The basic barometer can be used to measure the height of a building. If the barometric readings at the top and the bottom of a b

erma4kov [3.2K]

Answer:

$h = 269.6 m$

Explanation:

Pressure at the bottom of the building and at the top of the building must be related as

$P_{top} = P_{bottom} - \rho g h$

$P_{top} = 730 mm Hg$

$P_{bottom} = 755 mm Hg$

now we will have

$(755 \times 10^{-3})(13.6 \times 10^3)(9.81) = P_{bottom}$

$P_{bottom} = 1.007 \times 10^5 Pa$

$P_{top} = (730\times 10^{-3})(13.6 \times 10^3)(9.81)$

$P_{top} = 0.974 \times 10^5$

now we have

$(1.007 - 0.974)\times 10^5 = 1.25 (9.81) h$

$h = 269.6 m$

7 0

3 years ago

A car, X, with a mass of 1500 kg is moving west with an acceleration of 0.50 m/s2. A second car, Y, of equal mass is heading eas

ehidna [41]

Answer:

A

Explanation:

8 0

3 years ago

An 8.00 g bullet is fired into a 250 g block that is initially at rest at the edge of a table of 1.00 m height. The bullet remai

Vsevolod [243]

<span>79.75m/s .................................</span>

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3 years ago

The mass of the uniform cantilever is 1100 kg. Determine the force on the beam at A. Determine the force on the beam at B. Use C

Mashcka [7]

Answer:

Force A=-−2,697.75 N

Force B=13, 488.75 N

Explanation:

Taking moments at point A, the sum of clockwise and anticlockwise moments equal to zero.

25 mg-20Fb=0

25*1100g=20Fb

Fb=25*1100g/20=1375g

Taking g as 9.81 then Fb=1375*9.81=13,488.75 N

The sum of upward and downward forces are same hence Fa=1100g-1375g=-275g

-275*9.81=−2,697.75. Therefore, force A pulls downwards

Note that the centre of gravity is taken to be half the whole length hence half of 50 is 25 m because center of gravity is always at the middle

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3 years ago