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2 years ago

13

A football player kicks a ball with an initial velocity of 25 m/s at an angle of 53 degrees above the horizontal. The vertical c

omponent of the initial velocity of the ball

1 answer:

Verdich [7]2 years ago

7 0

Answer:

20 m/s

Explanation:

initial velocity, u= 25m/s

u has two components. one in horizontal and in one vertical.

so,

u sin theta = vertical component.

=> u sin theta = 25× 4/5

= 20 m/s

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Can there be displacement of an object in the absence of any force acting on it? Think, Discuss it with your friends and teacher

Fudgin [204]

Answer:

An object can have a displacement in the absence of any external force acting on it

Explanation:

When a object moves with a constant velocity (v), then it gets displaced in the direction of motion but the net external force experienced by the object is zero.

F external =ma

If object moves with constant velocity, acceleration is zero.

Since, a=0 ⟹F external =0

Using s=ut+ 1/2 at ^2

⟹ Displacement s=ut (∵a=0)

Hence, an object can have a displacement in the absence of any external force acting on it

Hope this helped you:)

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2 years ago

Physics question please show work for brainliest :)

navik [9.2K]

A. A car comes equipped with side airbags. I don't know how I'm supposed to show work but that's the answer

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3 years ago

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A 2.3 kg particle-like object moves in a plane with velocity components vx = 40 m/s and vy = 75 m/s as it passes through the poi

Sonbull [250]

Answer:

(a) $\overrightarrow{L}=885.5\widehat{k}$

(b) $\overrightarrow{L}=1046.5\widehat{k}$

Explanation:

mass, m = 2.3 kg

vx = 40 m/s

vy = 75 m/s

(a) Angular momentum is given by

$\overrightarrow{L}=\overrightarrow{r}\times \overrightarrow{p}$

Where, p is the linear momentum and r is the position vector about which the angular momentum is calculated.

Here, $\overrightarrow{r}=3\widehat{i}-4\widehat{j}$

$\overrightarrow{p}=m\overrightarrow{v}$

$\overrightarrow{p}=2.3\left ( 40\widehat{i}+75\widehat{j} \right )$

$\overrightarrow{p}= 92\widehat{i}+172.5\widehat{j}$

So, the angular momentum

$\overrightarrow{L}=\left ( 3\widehat{i}-4\widehat{j} \right )\times\left ( 92\widehat{i}+172.5\widehat{j} \right )$

$\overrightarrow{L}=885.5\widehat{k}$

(b) Here, $\overrightarrow{r}=(3+2)\widehat{i}+(-4+2)\widehat{j}$

$\overrightarrow{r}=5\widehat{i}-2\widehat{j}$

$\overrightarrow{L}=\left ( 5\widehat{i}-2\widehat{j} \right )\times\left ( 92\widehat{i}+172.5\widehat{j} \right )$

$\overrightarrow{L}=1046.5\widehat{k}$

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3 years ago

DESPERATE WILL GIVE BRAINLSIT AND THANKS

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Hello!

My best guess would be hydrogen and oxygen.

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3 years ago

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Once Kate's kite reaches a height of 50 ft (above her hands), it rises no higher but drifts due east in a wind blowing 7 ft d

Margaret [11]

Answer:

dz = 7.136 (answer)

Explanation:

given height for kate's kite = 50 ft (say y)

due to drift it move towards east = dx = 7 ft

string maximum length = 107 ft ( say z)

we have to find change in z

that is dz

it will form a right angle triangle for x , y and z where x is base y is height and z is hypotenuse

so we get according to Pythagoras Theorem

$z^2 = x^2+y^2\\$ ...............(i)

by derivative both side consider y as constant

$2zdz = 2xdx\\dz = {xdx }/z$

from (i) equation

$x = \sqrt{z^2-y^2}$

$dz = \sqrt{z^2-y^2}dx/z$

now put the value and find dz

$dz = (\sqrt{120^2-50^2)}7/107\\ =((\sqrt{14400 -2500} )\times7)/107$

after solving these we get

$dz =\frac{109.08\times7}{107}$

dz = 7.136 (answer)

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3 years ago