A) In the case of the Boundary Thickness Layer we use the given formula,
We know as well that,
Re = Número de Reynolds =
Where,
U = velocity
= kinematic viscosity
For water, kinematic viscosity,
So,
B) For flat plate boundary layer. Given the Critical Reynolds Number.= 5*10^5 we know that is equal to Re above.
Thus,
C. Wall shear stress,
For water, dynamic viscosity, = 2.344*10^-5 lbf-s/ft^2
Answer:
94.67 N
Explanation:
Consider a free body diagram with force, F of 41 N applied at an angle of 37 degrees while the weight acts downwards. Resolving the force into vertical and horizontal components, we obtain a free body diagram attached.
At equilibrium, normal reaction is equal to the sum of the weight and the vertical component of the force applied. Applying the condition of equilibrium along the vertical direction.
Substituting 70 N for W, 41 N for F and for 37 degrees
N=70+41sin37=94.67441595 N and rounding off to 2 decimal places
N=94.67 N
