A 300-kg bear grasping a vertical tree slides down at constant velocity. The friction force between the
tree and the bear is
This question involves the concepts of Newton's Second Law of Motion.
The acceleration of the bowling ball will be "0.67 m/s²".
<h3>Newton's Second Law of Motion</h3>
According to Newton's Second Law of Motion, when an unbalanced force is applied on an object, it produces an acceleration in it, in the direction of the applied force. This acceleration is directly proportional to the force applied and inversely proportional to the mass of the object. Mathematically,

where,
- a = acceleration = ?
- F = Magnitude of the applied force = 6 N
- m = Mass of the ball = 9 kg
Therefore,

a = 0.67 m/s²
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Answer:
if I aint wrong it would 2nd one
When the car moves and makes a sound that is louder that when the car is just sitting there
The gravitational force on the car is
(9.8 m/s^2) x (the car's mass in kg).
The unit is newtons.