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tekilochka [14]
3 years ago
15

Increasing which two things would increase gravitational potential energy?

Physics
1 answer:
sukhopar [10]3 years ago
7 0

Answer:

Mass and height

Explanation:

Gravitational potential energy is energy an object possesses because of its position in a gravitational field. The most common use of gravitational potential energy is for an object near the surface of the Earth where the gravitational acceleration can be assumed to be constant at about 9.8 m/s2.

Which is represented as;

PE_g=mgh

PE_g stands for gravitational potantial energy,

m stands for mass of object,

g is the gravitational constant and

h is the height.

Here we see that mass of object and height is directly proportional to the gravitational potential energy.

That means increasing in mass and height will result in increasing gravitational potential energy.

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the choices below each describe the appearance of an h-r diagram for a different star cluster. which cluster is most likely to b
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The cluster that is most likely to be located in the halo of our galaxy is the diagram that shows main-sequence stars of every spectral type except O, along with a few giants and supergiants.

<h3>What are star clusters?</h3>

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Because of their location on the dusty spiral arms of spiral galaxies, they are sometimes referred to as galactic clusters. Stars in an open cluster share a common ancestor as they all formed from the same massive molecular cloud.

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7. The energy source used to produce most of the electrical energy in the United States is ____________________.
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A 0.50-kg red cart is moving rightward with a speed of 40 cm/s when it collides
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The momentum of the red cart before the collision is 0.2 kgm/s and the blue cart is 0.

The momentum of the red cart after the collision is 0.05 kgm/s and the blue cart is 0.15 kgm/s.

The change in momentum of the system of the carts is 0.

<h3>Initial momentum of the carts before collision</h3>

The momentum of the carts before the collision is calculated as follows;

P(red) = 0.5 kg x 0.4 m/s = 0.2 kgm/s

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<h3>Momentum of the carts after collision</h3>

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<h3>Change in momentum of the carts</h3>

\Delta P = P_f - P_i

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ΔP = 0

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