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tekilochka [14]

3 years ago

15

Increasing which two things would increase gravitational potential energy?

1 answer:

sukhopar [10]3 years ago

7 0

Answer:

Mass and height

Explanation:

Gravitational potential energy is energy an object possesses because of its position in a gravitational field. The most common use of gravitational potential energy is for an object near the surface of the Earth where the gravitational acceleration can be assumed to be constant at about $9.8 m/s2.$

Which is represented as;

$PE_g=mgh$

$PE_g$ stands for gravitational potantial energy,

m stands for mass of object,

g is the gravitational constant and

h is the height.

Here we see that mass of object and height is directly proportional to the gravitational potential energy.

That means increasing in mass and height will result in increasing gravitational potential energy.

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Declination of a star is similar to Earth's:<br> latitude<br> longitude<br> rotation<br> inclination

balu736 [363]

Ight Ascension and Declination<span> are a system of coordinates used in astronomy to determine the location of</span>stars<span>, planets and other objects in the night sky. They are </span>similar<span> to the system of </span>longitude<span> and </span>latitude<span>used to locate places on </span>Earth<span>.</span>

6 0

3 years ago

Read 2 more answers

Consider your favorite radio station. AM radio has a frequency between 535 kilohertz and 1605 kilohertz, and FM radio has a freq

zzz [600]

Answer

The wavelength for 550 kHz signal is

$\lambda = \dfrac{3.00 \times 10^8}{550\times 10^3}$

λ = 545.45 m

The wavelength for 1600 kHz signal is

$\lambda = \dfrac{3.00 \times 10^8}{1600\times 10^3}$

λ = 187.5 m

The wavelength for 88 MHz signal is

$\lambda = \dfrac{3.00 \times 10^8}{88\times 10^6}$

λ = 3.41 m

The wavelength for 108 MHz signal is

$\lambda = \dfrac{3.00 \times 10^8}{108\times 10^6}$

λ = 2.78 m

7 0

3 years ago

A car with a mass of 1.1 × 103 kilograms hits a stationary truck with a mass of 2.3 × 103 kilograms from the rear end. The initi

snow_lady [41]

Answer:

The velocity of the truck after this elastic collision is 15.7 m/s

Explanation:

It is given that,

Mass of the car, $m_1=1.1\times 10^3\ kg$

Mass of the truck, $m_2=2.3\times 10^3\ kg$

Initial velocity of the car, $u_1=22\ m/s$

Initial velocity of the truck, u₂ = 0

After the collision the velocity of the car is, v₁ = -11 m/s

Let v₂ is the velocity of the truck after this elastic collision. Using the conservation of momentum as :

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$

$1.1\times 10^3\times 22+0=1.1\times 10^3\times (11)+2.3\times 10^3\times v_2$

$v_2=15.7\ m/s$

So, the velocity of the truck after this elastic collision is 15.7 m/s. Hence, the correct option is (c).

4 0

3 years ago

A ball player catches a ball 3.55 s s after throwing it vertically upward. with what speed did he throw it

Hatshy [7]

Answer:

i believe he threw the ball up at about 18 mph

Explanation:

5 0

3 years ago

The self inductance relates the magnetic flux linkage to the current through the coil. Calculate the self inductance L in units

Katen [24]

Answer:

Self inductance, $L=127\ \mu H$

Explanation:

It is given that,

Length of the coil, l = 5 cm = 0.05 m

Area of cross section of the coil, $A=3\ cm^2=0.0003\ m^2$

Number of turns in the coil, N = 130

The self inductance relates the magnetic flux linkage to the current through the coil and it is given by :

$L=\dfrac{\mu_oN^2A}{l}$

$L=\dfrac{4\pi \times 10^{-7}\times (130)^2\times 0.0003}{0.05}$

L = 0.000127 Henry

or

$L=127\ \mu H$

So, the self inductance of the coil is 127 microhenry. Hence, this is the required solution.

6 0

4 years ago