Answer: 339K
Explanation:
Initial pressure P1 = 14.9 atm
Final pressure P2 = 16.5 atm
Original temperature T1 = 33.1 °C
Convert Celsius to Kelvin
(33.1°C + 273 = 306.1K)
Final temperature T2 = ?
Apply the formula for Pressure's law
P1/T1.= P2/T2
14.9atm/306.1K = 16.5atm/ T2
To get T2, cross multiply
14.9 x T2 = 16.5 x 306.1
14.9T2 = 5050.65
T2 = (5050.65/14.9)
T2 = 339K
Thus, the final temperature of the gas would be 339K
For the equilibrium that
you have written...
<span>H2CO3 + H2O <==> HCO3-
+
H3O+ </span>
<span>acid base conjugate base conjugate acid</span>
We know that carbon dioxide
reacts with water to form "carbonic acid." However what we really
call as carbonic acid is not the weak acid H2CO3; H2CO3 does not even exist in
aqueous solution. What really we call as carbonic acid is simply CO2 dissolved
in water which is in equilibrium with small amounts of H+ and HCO3-. HCO3^- is
the intermediate substance between CO2 and CO3^2-. By adding OH- to HCO3^- we produce
CO3^2-. Adding H+ to HCO3 produces CO2.
CO2(aq) + H2O(l) <==> H+ + HCO3^- ........
carbonic acid .... midrange pH values
HCO3^- + OH- <==> CO3^2- + H2O(l) ....... formation of
carbonate ion .... basic
HCO3^- + H+ <==> CO2(g) + H2O(l) .......... formation
of carbon dioxide .. acidic
Acid: H2CO3
Conjugate Base: <span>HCO3- </span>
Base: H2O
Conjugate Acid: <span>H3O+ </span>
Answer:
2 mL of Solution A must be added to Solution B to give a buffer that is equimolar.
Explanation:
Given the data in the question;
First we determine the number of sodium acetate;
⇒ molarity × volume ( L )
⇒ 0.16 × 2.0 mL
⇒ 0.16 × 0.002 L
⇒ 0.00032
Now, Molarity of sodium acetate = moles / Volume(L)
⇒ ( 0.00032 / 50 ) × 1000
⇒ 0.0064
Since number of moles of acetic acid that should be added tp make equimolar solution is 0.00032
and Molarity of acetic acid is 0.16 molL⁻¹
Let X represent the volume that should be added.
so;
Molarity = Moles / Volume (L)
we substitute
0.16 = (0.00032 / X) × 1000
0.16 = 32 / X
X = 0.32 / 0.16
X = 2 mL
Therefore, 2 mL of Solution A must be added to Solution B to give a buffer that is equimolar.
Answer:
m = 7.29 grams
Explanation:
Given that,
Initial temperature, T₁ = 25ºC
Final temperature, T₂ = 31.5ºC
The specific heat of the metal is 0.89 J/gºC.
We know that the heat released due to the change in temperature is given by :
So, the mass of the piece is equal to 7.29 grams.
The answer is (4) the particles have more energy and collide more frequently.