1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
gregori [183]
3 years ago
12

When the pressure is 1.22 atm, a sample of hydrogen gas has a volume of 1.88L. What is its volume if the pressure is increased t

o 1.45 atm?
Chemistry
1 answer:
Evgesh-ka [11]3 years ago
6 0

Answer:

1.58 L

Explanation:

Use Boyle's law, which is defined as

p1v1 = p2v2

In this case we're solving for V2 because the rest of the variables are given.

p1 = 1.22 atm

v1 = 1.88L

p2 = 1.45 atm

v2 = ?

p1v1 = p2v2

(1.22 atm)(1.88L) = (1.45 atm)(v2)

v2 = (1.22 atm)(1.88L) ÷ (1.45 atm) = 1.58 L

You might be interested in
Formic acid (HCO2H) has a dissociation constant of 1.8 x 10^-4 M. The acid dissociates 1:1. What is the [H+] if 0.35 mole of for
Tju [1.3M]
Initial [ HCO2H] = moles * volume 
                           =0.35 moles * 1 L = 0.35 M

by using ICE table:

              HCO2H ↔ H+  + HCO2-
initial      0.35 M        0          0
change  - X             +X          +X
Equ       (0.35 - X)       X          X

∴ Ka = [H+][HCO2-] / [HCO2H]

by substitution:

1.8 x 10^-4 =  X^2 / (0.35-X) by solving for X

∴ X = 0.0079 or 7.9 x 10^-3

∴ [H+] = X = 7.9 x 10^-3 M
7 0
3 years ago
Which element in the list is the most reactive?<br><br> C<br><br> Ba<br><br> S<br><br> Cs
Tems11 [23]

Answer:

Cs

Explanation:

This element is the farthest right, and lowest meaning that the reactivity of it is very high.

1. valence electrons and electronegativity

2. Both reactivity and electronegativity decrease down a group.

3. Electronegativity decreases down a group, and reactivity increases down a group.

4. The number of valence electrons increases from left to right.

5. Cs

{quizlet: captncrun}

4 0
2 years ago
The mother of a child has a cleft chin while the father of a child has a smooth chin. The child also has a cleft chin
timurjin [86]
The mother has stronger genetics
5 0
3 years ago
Jenna built the electrical circuit seen here. What would happen to the electrical energy if Jenna removed one of the clips on th
otez555 [7]

Answer: Option (D) is the correct answer.

Explanation:

An electric circuit works well when all the connections are complete but if any of the connections in the circuit is loose or disconnected then it is possible that current will not flow from the circuit.

Therefore, when Jenna removed one of the clips on the battery then circuit becomes incomplete and as a result there will no flow of current.

Thus, we can conclude that the electrical energy would stop because the circuit is incomplete.

6 0
2 years ago
Cu has an anomalous electron configuration. write the observed electron configuration of cu.
xenn [34]
1s2 2s2 2p6 3s2 3p6 3d10 4s1
5 0
3 years ago
Read 2 more answers
Other questions:
  • Complete the statements by writing the number
    7·1 answer
  • what events and experiences lead bruno to gradually give up some of his innocence and see things differently
    7·1 answer
  • Which of the following is true regarding Keq?
    7·1 answer
  • Suppose you had an organic molecule such as cystine, and you chemically removed the --nh2 group and replaced it with --cooh. Dra
    5·1 answer
  • What is the wavelength of a photon with a frequency of 7.81 x 1014 Hz?
    6·1 answer
  • Un niño de 9 años se encuentra balanceándose en un columpio, si el columpio se encuentra en equilibrio y la cadena que soporta l
    15·1 answer
  • What type of elements are in s-block
    14·1 answer
  • Identify the solute in the following: carbon dioxide dissolved in water
    5·1 answer
  • Describe the relationship between the strength of a force on an object and the subsequent t change in velocity
    10·1 answer
  • How many atoms are present in 0.529 moles of Li?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!