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earnstyle [38]
2 years ago
6

What is the wavelength of a photon with a frequency of 7.81 x 1014 Hz?

Chemistry
1 answer:
yulyashka [42]2 years ago
8 0

Explanation:

If you know the frequency of the photon, you can calculate the wavelength using the equation λ=cν where c is the speed of light and ν is the frequency.

λ=cν

f=T^-1,f=1/7.81×1014s

c=3×10^8m/s

λ=3×10^8m/s×1/7.81.×1014s

λ=37881.94m

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Part V Write the (a) half reaction of oxidation, (b) half reaction of reduction, & (c) the balanced redox reaction for all o
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Answer:

Explanation:

a. Oxidation : 2O + 4e^- ------> 2O^2-

b. Reduction: 2Sr - 4e- -------> Sr^2+

c. Balanced redox reaction

2Sr + O2 ------------> 2Sr O

Oxidation and reduction can be defined by various means, addition of oxygen, removal of hydrogen, removal of electrons. For this reaction, this definition is used, oxidation is the loss of electrons while reduction is the gaining of electrons.

In (a) oxidation half reaction, the valency of oxygen is zero and then moves into lossing two electrons resulting into -2 valency.

In (b) reduction half reaction, the valency of Sr is zero and gains electrons resulting into valency of 2.

In the overall redox reaction, Sr and O2 with valency of 0 each reacts together and form SrO with valency of 2 and -2 respectively, which gives 0 and then balances the equation.

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3 years ago
What is a forensic paleontologist?<br>dum it down for me​
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Answer:

Simple Definition: A Tool for “Intelligence” and Investigation

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4 0
2 years ago
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Where do producers belong on the food chain?
Akimi4 [234]
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4 0
3 years ago
C3H8 + 5O2 → 3CO2 + 4H2O
trasher [3.6K]

Answer:

16.5moles of CO2

Explanation:

Molar mass of O2 is 32g/Mol

No of mole = 880/32 = 27.5 moles

27.5 Mol of O2 gives X mole of CO2

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No of mole of CO2 = (27.5×3)/ 5 = 16.5moles

7 0
3 years ago
(A tablet containing calcium carbonate and fillers with a mass of 1.631 g was dissolved in HCl. After the fillers were filtered
FrozenT [24]

Answer:

1) 0.825 grams is the mass of pure calcium carbonate product collected at the end of the experiment.

2) The mass % calcium carbonate in the tablet is 50.58%.

3) The mass % of calcium in calcium carbonate  is 40.00 %.

4) Mass of calcium in a tablet is 0.33 g.

Explanation:

Mass of tablet = 1.631 g

Mass of the watch glass = 46.719 g

Mass of the watch glass + mass of calcium carbonate = 47.544 g.

Mass of calcium carbonate = 47.544 g - 46.719 g = 0.825 g

0.825 grams is the mass of pure calcium carbonate product collected at the end of the experiment.

Mass of calcium carbonate = 0.825 g

Percentage of calcium in tablet:

\%=\frac{\text{Mass of calcium carbonate }}{\text{Mass of tablet}}\times 100

\%=\frac{0.825 g}{1.631 g}\times 100=50.58\%

The mass % calcium carbonate in the tablet is 50.58%.

Percentage of calcium in calcium carbonate :

Molar mass of calcium carbonate = 100 g/mol

Atomic mass of calcium = 40 g/mol

Percentage of calcium in calcium carbonate :

\%=\frac{\text{atomic mass of calcium}}{\text{Molar mass of}CaCO_3}\times 100

\%=\frac{40 g/mol}{100 g/mol}\times 100=40.00\%

The mass % of calcium in calcium carbonate  is 40.00 %.

Mass of calcium carbonate = 0.825 g

The mass % of calcium in calcium carbonate  is 40.00 %.

Mass of calcium in a tablet : x

40.00\%=\frac{\text{Mass of calcium in a tablet}}{0.825 g}\times 100

x=40.00\times \frac{0.825 g}{100}=0.33 g

Mass of calcium in a tablet is 0.33 g.

3 0
3 years ago
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