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3 years ago

Which of the following is true regarding Keq?

Chemistry

1 answer:

grandymaker [24]3 years ago

6 0

Answer:

option b is true

Explanation:

Since the equilibrium constant Kp is defined as the ratio of [products]/[reactants] ( option c is false) , then Kp units depends on the order of reaction of the reactants and the number of reactants and products involved ( option a is false).

for example if the concentration is expressed as M (molarity)

Keq= [A]/[B]*[C] then Kep has as units 1/M

Also t a specific temperature , the equilibrium constant represents the relationship between concentrations of reactants and products , and its fixed at constant temperature (option b is true).

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3 years ago

Root Mean Square Speed and Graham's Laws

tiny-mole [99]

Answer:

1. 7.0 u; 2. 81 u; 3. 12.7 h.

Step-by-step explanation:

<em>Graham’s Law </em>applies to the diffusion of gases:

The rate of diffusion (r) of a gas is inversely proportional to the square root of its molar mass (M).

r = 1/√M

If you have two gases, the ratio of their rates of diffusion is

r₂/r₁ = √(M₁/M₂)

1. Molecular mass

r₂/r₁ = (2.5r₁)/r₁ = 2.5

2.5 = √(44.01/M₂)

Square both sides: 6.25 = 44.01/M₂

Multiply each side by M₂: 6.25M₂ = 44.01

Divide each side by 6.25: M₂ = 7.0 u

The molecular mass of the gas is 7.0 u.

2. Molecular mass

r₂/r₁ = (r₁/1.7)/r₁ = 1/1.7

1/1.7 = √(28.01/M₂)

Square both sides: 1/2.89 = 28.01/M₂

Multiply each side by M₂: M₂/2.89 = 28.01

Multiply each side by 2.89: M₂ = 81 u

The molecular mass of the gas is 81 u.

3. Time for diffusion

The time for effusion is inversely proportional to the rate. The faster the rate, the slower the time. Thus,

t₂/t₁ = √(M₂/M₁)

Multiply each side by t₁

t₂ = t₁√(M₂/M₁) = 4.5√(16.04/2.016) = 4.5√7.956 = 4.5 × 2.82 = 12.7 h

It would take methane 12.7 h to diffuse.

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4 years ago

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bekas [8.4K]

Answer:

Explanation:

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3 years ago

A compound has a molar mass of 92.02 grams/mole, and its percent composition is 30.4% nitrogen (N) and 69.6% oxygen (O). What is

Maru [420]

Answer:- Molecular formula is $N_2O_4$ .

Solution:- From given percentages We calculate the moles of N and O and then the mol ratio that gives the empirical formula of the compound. Empirical formula mass is calculated for the empirical formula and then we divide the molar mass by empirical formula mass to find out the number of empirical formula units that makes the molecular formula of the compound. empirical formula is multiplied by the number of empirical formula units. the calculations are shown below:

$30.4gN(\frac{1mol}{14g})$ = 2.17 mol N