Factor. 2x² - 5xy - 3y^2

Mathematics

1 answer:

NeX [460]3 years ago

8 0

Answer:

2x² - 5xy - 3y²= (2x+y)(x-3y)

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If A={1,2,3}, find the relation in A×S satisfying the condition x+y<5.

Sonja [21]

Answer: This is copied from the internet:

Step-by-step explanation:

Answer:

For function, every element of the domain must have a unique image in co-domain...

(A)Let us redefine each function as a set of ordered pairs

and see if they satisfy the above condition (A) of a function f1={(1,2),(2,3),(3,4)} ; (4,5) cannot be an ordered pair as 5 does not belong to co-domain , Thus the element 4 of domain does not have an image.

f2={(1,4),(2,3),(2,4),(3,2)(3,3),(3,4),(4,1),(4,2),(4,3),(4,4)}

The uniqueness is violated as the elements have not one but many images.

f3={(2,1),(3,2),(3,1),(4,1),(4,2),(4,3)} Not a function as in f2 uniqueness is violated.

f4={(1,4),(2,3),(3,2)(4,1)} It is a function as each element has a unique image.

5 0

3 years ago

Romashka [77]

9.42 Units

Step-by-step explanation:

Since the angle shown is 90 degrees we can deduce that the rest of the arc is 270 degrees therefore we can make the fraction:

270/360; 360 being the total angle measurement of a circle

270/360 simplifies to 3/4

The fraction represents how much of the circle that arc covers

Now we have to find the circumference which would be

2(3.14)r

r = 2 therefore: 2(3.14)2 = 12.56

Now that we have the circumference of the WHOLE circle we multiply it by 3/4 to find out the arc length

Which gives us 9.42

8 0

3 years ago

PICK ON OF THE FOLLOWING! (imagine attached)

Aleks04 [339]

Answer:

Step-by-step explanation:

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2 years ago

The value of log3 5 x log25 9 is

Rama09 [41]

$\log_{3}5\cdot\log_{25}9=\dfrac{1}{\log_{5}3}\cdot\log_{25}9=\dfrac{1}{\log_{5}3}\cdot\log_{5^2}9=\dfrac{1}{\log_{5}3}\cdot\dfrac{1}{2}\log_{5}9=\\\\\\=
\dfrac{1}{\log_{5}3}\cdot\dfrac{1}{2}\log_{5}3^2=\dfrac{1}{\log_{5}3}\cdot\dfrac{2}{2}\log_{5}3=\dfrac{1}{\log_{5}3}\cdot\log_{5}3=\dfrac{\log_{5}3}{\log_{5}3}=\boxed{1}$