Answer:
Step-by-step explanation:
you know the total angle is 180° from A to D
and you know that ∠BEC is 90°
also you are told that ∠CED is 18°
and that ∠AEB is 4x°
so just put that all together
180=90 + 18 +4x
now solve for X
180-90-18=4x
72=4x
18 = x
so now you know X
now solve ∠AEB
4(18) = 72°
∠AEB= 72°
:)
It's about 54.3 (repeating)
The answer is B) 43<span>°
Angle ADB is an inscribed angle which means arc AB has an angle twice that of angle ADB. The angle of the arc would be the same as that of the central angle AOB. So, mAOB = 86</span>°. And since, mAOB = mBOC, then mBOC = 86° and arc BC has a measure of 86° as well. Angle BDC intercepts the arc BC which means half of the angle of arc BC is mBDC. So, mBDC = 43<span>°.</span>
Answer:
I'm hoping the answer should be D. 9 units.
Answer:
x = 25°
Step-by-step explanation:
2x-10°+2x-10°+100°=180°[sum of angles in a triangle ]
4x+80°=180°
4x=100°
x=25°