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3 years ago

Which measurement shows a valid estimate for this ruler? 2.3 cm 2.35 cm 2.350 cm

Chemistry

1 answer:

tekilochka [14]3 years ago

3 0

Answer:

B. 2.35

Explanation:

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Disintegration is the word geologists use forA.When a rock becomes moist.B.When rock is physically broken into smaller pieces.C.

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C would be the best answer because its the most logical one

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2 years ago

the atomic masses of 63 cu (69.17 percent) and 65 cu (30.83 percent) are 62.94 and 64.93 amu, respectively. calculate the averag

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Answer:

The average atomic mass of copper is 63.55 amu.

Explanation:

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1 year ago

A gaseous mixture of o2 and n2 contains 35.8 % nitrogen by mass. what is the partial pressure of oxygen in the mixture if the to

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2 years ago

How do you balance this chemical equation?

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2 years ago

A piece of unknown metal with mass 30 g is heated to 110.0 °C and dropped into 100.0 g of water at 20.0 °C. The final temperatur

Ymorist [56]

<u>Answer:</u> The specific heat of metal is 0.821 J/g°C

<u>Explanation:</u>

When metal is dipped in water, the amount of heat released by metal will be equal to the amount of heat absorbed by water.

$Heat_{\text{absorbed}}=Heat_{\text{released}}$

The equation used to calculate heat released or absorbed follows:

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]$ ......(1)

where,

q = heat absorbed or released

$m_1$ = mass of metal = 30 g

$m_2$ = mass of water = 100 g

$T_{final}$ = final temperature = 25°C

$T_1$ = initial temperature of metal = 110°C

$T_2$ = initial temperature of water = 20.0°C

$c_1$ = specific heat of metal = ?

$c_2$ = specific heat of water = 4.186 J/g°C

Putting values in equation 1, we get:

$30\times c_1\times (25-110)=-[100\times 4.186\times (25-20)]$

$c_1=0.821J/g^oC$

Hence, the specific heat of metal is 0.821 J/g°C

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2 years ago