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sveta [45]
3 years ago
5

Question 1 (4 points)

Chemistry
1 answer:
Vilka [71]3 years ago
7 0
To be honest answer might be a
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A solution containing 292 g of Mg(NO3)2 per liter has a density of 1.108 g/mL. The molality of the solution is:
serg [7]

Answer: D) 2.41 m

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

Molality=\frac{n}{W_s}

where,

n = moles of solute

 W_s = weight of solvent in kg

moles of solute =\frac{\text {given mass}}{\text {molar mass}}=\frac{292g}{148g/mol}=1.97moles

volume of solution = 1L = 1000 ml      (1L=1000ml)

Mass of solution={\text {Density of solution}}\times {\text {Volume of solution}}=1.108g/ml\times 1000ml=1108g

mass of solute = 292 g

mass of solvent = mass of solution - mass of solute = (1108- 292) g = 816g = 0.816 kg

Now put all the given values in the formula of molality, we get

Molality=\frac{1.97moles}{0.816kg}=2.41mole/kg

Therefore, the molality of solution will be 2.41 mole/kg

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