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diamong [38]
3 years ago
6

Rafael lives near a road at the bottom of the hill. His parents are concerned that soil will wash off the hill and rocks will fa

ll onto the road. Rafeal converts an investigation to find out if grass growing on a hillside will help stop soil erosion. He collects two samples of the same size and type of soil. One sample of soil has grass growing on it and the other does not. He places each sample of soil in a small tray. For his investigation, Rafael pours the same amount of water onto both samples of soil. He uses a large tray to collect water that may flow through the soil. Which practice shows the best way for Rafael to set up this investigation?

Physics
1 answer:
timofeeve [1]3 years ago
7 0

Answer:

The first picture/option

Explanation:

<em>The first picture/option shows the best way for Rafael to set up the investigation.</em>

The experimental set-up must be in a sloppy position in order to simulate the condition that is characteristic of the bottom of the hill where he stays. Hence, the two soil samples must be tilted in order to determine if the grass can help to stop the washing down of the soil from the top of the hill.

The two options following the first option do not fulfill the condition of the same treatment. Both soil samples must be subjected to the same treatment condition in order for the outcome to be valid. The last option could have also been admissible but did not simulate the hill/slope conditions of where Rafael stays.

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sleet_krkn [62]

An equation showing the relationship between the THREE forces is R -W +F= 0

<h3>What is moment of force?</h3>

The equal and opposite force acting at a point from the axis of rotation is called the moment of force.

M = F x r

Given is a wheelbarrow and stones with a total mass of 43 kg. The wheelbarrow is in equilibrium with two of the three forces acting on it

Taking moment about the wheel, we get

-43x 9.81 x 0.6 + F x 1.5 =0

F = 43 x 0.6/1.5

F = 168.732 N (upward force)

Summation of forces in y direction is zero.

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brainly.com/question/6278006

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3 0
2 years ago
The motion of a particle connected to a spring is described by x = 10 sin (pi*t). At
Gekata [30.6K]

To solve this problem we will first apply the principle of energy conservation, for which the elastic potential energy must be the same as the elastic kinetic energy of the simple harmonic movement of the system.

From this conservation it will be possible to find in total terms the total displacement of the system and thus replace it in the given function to find the time.

The potential energy stored would be

PE= \frac{1}{2} kx^2

The kinetic energy would be

KE = \frac{1}{2}m\omega (A^2-x^2)

Here,

A = 10m

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PE = KE

\frac{1}{2}kx^2 =\frac{1}{2} m\omega^2 (A^2-x^2)

\frac{1}{2}kx^2 = \frac{1}{2} m(x\frac{k}{m})(A^2-x^2)

x^2 = A^2 -x^2

2x^2 = A^2

x = \frac{A}{\sqrt{2}}

x = \frac{10}{\sqrt{2}}

So now using the equation previously given to describe the motion of the particle we have to

\frac{10}{\sqrt{2}} = 10 sin(xt)

\frac{1}{\sqrt{2}} = sin (xt)

sin^{-1} (\frac{1}{\sqrt{2}} ) = \pi t

\frac{\pi}{4} = \pi t

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Therefore the correct option is B.

6 0
3 years ago
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