To develop this problem it is necessary to apply the concepts given in the balance of forces for the tangential force and the centripetal force. An easy way to detail this problem is through a free body diagram that describes the behavior of the body and the forces to which it is subject.
PART A) Normal Force. 


Here, 
Normal reaction of the ring is N and velocity of the ring is v




PART B) Acceleration 





Negative symbol indicates deceleration.
<em>NOTE: For the problem, the graph in which the turning radius and the angle of suspension was specified was not supplied. A graphic that matches the description given by the problem is attached.</em>
 
        
             
        
        
        
Based on my information, this would actually be representing 
"the average kinetic energy of water particles". So, as you take notice that where this temperature is being located, and also, how this would be 

°C, this would make more sense for this to be representing as <span>the
 average kinetic energy of water particles.</span>
 
        
        
        
Answer:
Explanation:
circumference of the tyre = 2πr = 2 x 3.14 x 0.26 = 1.6328m
76000km = 76000000m
no of revolutions required 
= 76000000/1.6328 = 46546 revolutions.
 
        
             
        
        
        
Answer:
a = 0.8 m/s^2
Explanation:
Force equation: F = ma
F = ma -> a = F/m = 2.8*10^3 N / 3.5*10^3 kg = 0.8 m/s^2 
 
        
             
        
        
        
Answer:

Explanation:
<u>Tangent and Angular Velocities</u>
In the uniform circular motion, an object describes the same angles in the same times. If  is the angle formed by the trajectory of the object in a time t, then its angular velocity is
 is the angle formed by the trajectory of the object in a time t, then its angular velocity is

if  is expressed in radians and t in seconds the units of w is rad/s. If the circular motion is uniform, the object forms an angle
 is expressed in radians and t in seconds the units of w is rad/s. If the circular motion is uniform, the object forms an angle  in 2t, or
 in 2t, or  in 3t, etc. Thus the angular velocity is constant.
 in 3t, etc. Thus the angular velocity is constant.
The magnitude of the tangent or linear velocity is computed as the ratio between the arc length and the time taken to travel that distance:

Replacing the formula for w, we have
