Charges q3 and q5 are now replaced by two charges, q2 and q6, having equal magnitude and sign (-3.4 μC). Charge q2 is located at
1 answer:
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Answer:
1.37 rad/s
Explanation:
Given:
Total length of the tape is, m
Total time of run is, hours
We know, 1 hour = 3600 s
So, 2.1 hours = 2.1 × 3600 = 7560 s
So, total time of run is, s
Inner radius is,
Outer radius is,
Now, linear speed of the tape is,
Let the same angular speed be .
Now, average radius of the reel is given as the sum of the two radii divided by 2.
So, average radius is,
Now, common angular speed is given as the ratio of linear speed and average radius of the tape. So,
Therefore, the common angular speed of the reels is 1.37 rad/s.
ANSWER
EXPLANATION
First, let us make a sketch of the question:
From the diagram:
=> black line represents North
=> green line represents East
=> blue line represents West
=> red line represents South
From the diagram, we see that at the end of his journey, he returns to his start point.
Since displacement is the measure of the change in the position of an object and the boy's position did not change after the journey, his displacement is:
In order to solve the problem it is necessary to take into account the concepts related to the moment of inertia, and the center of mass of the object.
Our values are given by:
m = 0.514kg
I = 4.7m (each side)
A) For the case when the axis passes through the midpoints of opposite sidesand lies in the plane of the square. The formula is given by,
B) For the case when the axis passes through the midpoint of one of the sides and is perpendicular to the plane of the square. The formula is given by,
C) For the case when the axis lies in the plane of square f passes through two diagonally opposite particles,