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LiRa [457]
3 years ago
11

How much energy (in J) is lost when a sample of iron with a mass of 28.3 g cools from 66.0 degrees celsius to 24.0 degrees celsi

us.
Chemistry
1 answer:
pentagon [3]3 years ago
5 0

Answer:

Q = -535 J.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the lost energy according to the following and generic heat equation:

Q=mC(T_F-T_i)

Thus, since the specific heat of iron is 0.450 in the SI units, we can plug in the mass and temperatures to obtain:

Q=28.3g*0.450\frac{J}{g\°C} (24.0\°C-66.0\°C)\\\\Q=-535J

Regards

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Answer:

The answer to your question is: kc = 6.48

Explanation:

Data

             Given                 Molecular weight

CaO =    44.6 g                    56 g

CO₂ =     26 g                       44 g

CaCO₃ = 42.3 g                  100 g

Find moles

        CaO                 56 g ----------------  1 mol

                                 44.6 g --------------   x

                               x = (44.6 x 1) / 56 = 0.8 mol

        CO₂                 44 g -----------------  1 mol

                                26 g ----------------    x

                               x = (26 x 1 ) / 44 = 0.6  moles

        CaCO₃            100 g ---------------   1 mol

                                42.3g --------------    x

                              x = (42.3 x 1) / 100 = 0.423 moles

       

Concentrations

 

        CaO     =    0.8 / 6.5  = 0.12 M

         CO₂    =     0.6 / 6.5 = 0.09 M

        CaCO₃  =   0.423 / 6.5 = 0.07 M

Equilibrium constant =   \frac{[products]}{[reactants]}

Kc = [0.07] / [[0.12][0.09]

Kc = 0.07 / 0.0108

kc = 6.48

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