1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
LiRa [457]
3 years ago
11

How much energy (in J) is lost when a sample of iron with a mass of 28.3 g cools from 66.0 degrees celsius to 24.0 degrees celsi

us.
Chemistry
1 answer:
pentagon [3]3 years ago
5 0

Answer:

Q = -535 J.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the lost energy according to the following and generic heat equation:

Q=mC(T_F-T_i)

Thus, since the specific heat of iron is 0.450 in the SI units, we can plug in the mass and temperatures to obtain:

Q=28.3g*0.450\frac{J}{g\°C} (24.0\°C-66.0\°C)\\\\Q=-535J

Regards

You might be interested in
Why do electrons transition between energy levels within the atom, and how do we detect these transitions?
Sedaia [141]

Answer:

See explanation

Explanation:

Electrons transition between energy levels in an atom due to gain or loss of energy. An electron may gain energy and move from its ground state to one of the accessible excited states. The electron quickly returns to ground state, emitting the energy previously absorbed as a photon of light. The wavelength of light emitted is measured using powerful spectrometers.

Atoms can be excited thermally or by irradiation with light of appropriate frequency.

7 0
3 years ago
Write a reaction to describe the behavior of the following substances in water. please include all phases.
lorasvet [3.4K]

3NF3 + 5H2O → HNO3 + 2NO + 9HF

Nitrogen fluoride reacts with water to produce nitric acid, nitric oxide, and hydrogen fluoride. The reaction slowly takes place in a boiling solution.

CH2CH2 + H2O → CH3CH2OH

Ethylene is a hydrocarbon with water that creates ethanol and ethanol is an alcohol

4 0
3 years ago
24 POINTS!!!!!!!!!!
Oliga [24]
Your answer is going to be A, because it was shoved harder, it will go faster

8 0
3 years ago
Read 2 more answers
In a constant‑pressure calorimeter, 60.0 mL of 0.300 M Ba(OH)2 was added to 60.0 mL of 0.600 M HCl. The reaction caused the temp
Zepler [3.9K]

Answer:

ΔH = 57.04 Kj/mole H₂O

Explanation:

60ml(0.300M Ba(OH)₂(aq) + 60ml(0.600M HCl(aq)

=> 0.06(0.3)mole Ba(OH)₂(aq) + 0.60(0.6)mole HCl(aq)

=> 0.018mole Ba(OH)₂(aq) + 0.036mole HCl(aq)

=> 100% conversion of reactants => 0.018mole BaCl₂(aq) + 0.036mole H₂O(l) + Heat

ΔH = mcΔT/moles H₂O <==> Heat Transfer / mole H₂O

=(120g)(4.0184j/g°C)(27.74°C - 23.65°C)/(0.036mole H₂O)

ΔH = 57,042 j/mole H₂O = 57.04 Kj/mole H₂O

3 0
3 years ago
A detailed explanation, one paragraph of the colligative property being discussed and why that property changes the way that it
levacccp [35]
<span>
You can do it on the icing of roads, reverse osmosis for desalination of water, dissolved CO2 in soda cans, osmotic pressure involving blood vessels and IV solutions, etc.</span>
6 0
3 years ago
Other questions:
  • What are some physical properties of a candle
    11·2 answers
  • True or False: When you measure something with a ruler, you should NOT estimate an extra digit. You only need to report the numb
    9·1 answer
  • A compound has an empirical formula of C2H5. What is true about this empirical formula?
    9·1 answer
  • What causes objects to move or stay still?<br> Claim <br><br> Reasoning:<br><br> Evidence:
    15·2 answers
  • The total concentration of ions in a 0.75 M solution of HCl is
    15·1 answer
  • How many moles are in 1.82 x 10^20 atoms of silver?
    13·1 answer
  • What is the molar mass of just the O in CO2?
    6·1 answer
  • What does he want? change into passive ​
    12·1 answer
  • Which atom generally obtains a stable configuration by sharing electrons?
    12·2 answers
  • What is infrared energy? simplify it
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!