All categories

3 years ago

How many solutions?

Mathematics

2 answers:

Semmy [17]3 years ago

7 0

Answer: A Single Solution

Step-by-step explanation:

Stella [2.4K]3 years ago

6 0

Answer:

x=0

btw im dum the others guys right its a single solution

You might be interested in

If avogadro's number of pennies is divided equally among the 250. million men, women, and children in the united states, how man

Anastasy [175]

We divide the pennies 100 to convert pennies to dollar

1 pennies= 1/100 dollar

Then we will convert 6.02×10∧23 p to dollar

=1 dollar/100 pennie ×6.02×10∧23

= 6.02×10∧21

The total men and women and children in 250 m

=25×108

6.02×10∧21/2.5×10∧8

= 2.408×10∧13

6 0

4 years ago

HELP ASAP ILL GIVE BRAINLIST

SSSSS [86.1K]

Answer:

0.36

Step-by-step explanation:

To find the probability, just multiply.

probability of red candy * probability of pink cookie

0.9*0.4=0.36

I hope this helps!

4 0

3 years ago

A quality analyst of a tennis racquet manufacturing plant investigates if the length of a junior's tennis racquet conforms to th

Burka [1]

Answer:

Confidence interval : $21.506$ to $24.493$

Step-by-step explanation:

A quality analyst selects twenty racquets and obtains the following lengths:

21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

So, sample size = n =20

Now we are supposed to find Construct a 99.9% confidence interval for the mean length of all the junior's tennis racquets manufactured at this plant.

Since n < 30

So we will use t-distribution

Confidence level = 99.9%

Significance level = α = 0.001

Now calculate the sample mean

X=21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

Sample mean = $\bar{x}=\frac{\sum x}{n}$

Sample mean = $\bar{x}=\frac{21+25+23+22+24+21+25+21+23+ 26+ 21+24+22+ 24+23+21+ 21+ 26+23+ 24}{20}$

Sample mean = $\bar{x}=23$

Sample standard deviation = $\sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}$

Sample standard deviation = $\sqrt{\frac{(21-23)^2+(25-23)^2+(23-23)^2+(22-23)^2+(24-23)^2+(21-23)^2+(25-23)^2+(21-23)^2+(23-23)^2+(26-23)^2+(21-23)^2+(24-23)^2+(22-23)^2+(24-23)^2+(23-23)^2+(21-23)^2+(21-23)^2+(26-23)^2+(23-23)^2+(24-23)^2}{20-1}}$

Sample standard deviation= s = $1.72$

Degree of freedom = n-1 = 20-1 -19

Critical value of t using the t-distribution table $t_{\frac{\alpha}{2}$ = 3.883

Formula of confidence interval : $\bar{x} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}}$

Substitute the values in the formula

Confidence interval : $23 \pm 1.73 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $23 -3.883 \times \frac{1.72}{\sqrt{20}}$ to $23 + 3.883 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $21.506$ to $24.493$

Hence Confidence interval : $21.506$ to $24.493$

3 0

4 years ago

Read 2 more answers

What’s the answer to this?

antiseptic1488 [7]

Answer:

Step-by-step explanation:

4 0

3 years ago

How do I solve this problem

marysya [2.9K]

She can have 3 groups of tens and 8 groups of ones

3 0

3 years ago