How many solutions?
2 answers:
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Answer:
See explanation below
Step-by-step explanation:
<u>First we will solve the radical equation</u> (which I guess was problem 1),
Let's start by simplifying it:
Now we will solve the equation by squaring both sides of the equation:
So the calculation for x was that x = -10
However, this does not produce a solution to the equation: When we plug this value into the radical equation we get:
This happens because <u>when we first squared both sides of the equation in the first part of the problem we missed one value for x </u>(remember that all roots have 2 answers, a positive one and a negative one) while squares are always positive.
When we squared the root, we missed one value for x and that is why the calculation does not produce a solution to the equation.