I need help ASAP (get brainliest)

HELP!!!! I WILL MARK YOU BRAINLIST

Marina86 [1]

Answer:

k= 12 x= 5

Step-by-step explanation:

4 0

3 years ago

For which of these research situations would linear regression be the best statistical test to perform?

rjkz [21]

Answer:

C) independent variable = age

dependent variable = reaction time in milliseconds

Step-by-step explanation:

The linear regression statistical test is best used for research experiment where there is a single dependent and one independent variable whjre both variables are numeric. In the given options above, the city of residence, gender, college major and political affiliation are all possible categorical variables and age, salary, miles driven and reaction time are all numerical variables. Hence, the best situation in which to use linear regression is a test where both the independent and dependent variables are either age, salary, reaction time or miles driven.

7 0

3 years ago

PLEASE HELP!<br> Evaluate the expression 5(7 − 4)2 ÷ 3 + 11.

nataly862011 [7]

Answer:

26

Step-by-step explanation:

5(7 − 4)^2 ÷ 3 + 11.

PEMDAS says parentheses first

5(3)^2 ÷ 3 + 11.

Then exponents

5 (9)÷ 3 + 11.

Multiply and divide from left to right

45 ÷ 3 + 11

15 +11

26

5 0

3 years ago

Read 2 more answers

What is the simplified form of startroot startfraction 72 x superscript 16 baseline over 50 x superscript 36 baseline endfractio

ziro4ka [17]

The simplified form of the given equation is $=\frac{6}{5x^{10}}$

We have given that,

$\sqrt{\frac{72x^{16}}{50x^{36} }$

Apparently, you want to simplify the given equation,

$\sqrt{\frac{72x^{16}}{50x^{36} }$

The applicable rules of exponents are,

<h3>What is the exponent rule?</h3>

(a^b)(a^c) = a^(b+c)

1/a^b = a^(-b)

(a^b)^c = a^(bc)

So the expression simplifies as

$=\sqrt{\frac{72x^{16}}{50x^{36} }}\\\\=\frac{6}{5x^{10}}$

Therefore the simplified form of the given equation is $=\frac{6}{5x^{10}}$

To learn more about exponential form visit:

brainly.com/question/1269112

#SPJ1

6 0

2 years ago

Find T, N, and kappa for the plane curve Bold r left parenthesis t right parenthesis equalsleft parenthesis 7 Bold cos t plus

pickupchik [31]

Answer:

Step-by-step explanation:

r(t) = (7 cost + 7t sin t)i + (7 sin t - 7t cos t)j

$\frac{d \bar r t}{dt} =(7\frac{d}{dt}\cos t + 7\frac{d}{dt} (t \sin t)i+(7\frac{d}{dt} \sin t-7\frac{d}{dt} t \cos t)j$

$=(7(-\sin t)+7(1* \sin t+t \cos t))i+(7 \cost -7(1*\cos t - t \sin t))j\\\\=7((-\sin t+\sin t+t \cos t)i+(\cos t-\cos t+t \sin t)j)\\\\=7((t\cos t)i+(t\sin t)j)$

$\bar r'(t)=\frac{d \bar r t}{dt} =(7t\cos t)i+(7t\sin t)j---(1)\\\\11\bar r(t)=\sqrt{(7t\cos t)^2+(7t\sin t)^2}\\\\=\sqrt{49t^2(\cos^2t+\sin^2 t)} \\\\=7t$

$\bar T (t)=\frac{\bar r'(t)}{11\bar r(t)11} =\frac{(7t\cos t)i+(7t\sin t)j}{7t} \\\\\barT(t)=(\cos t)i+(\sin t)j$

$\bar T'(t)=\frac{d}{dt} (\cos t)i+\frac{d}{dt} (\sin t) j\\\\\bar T'(t)=(-\sin t)i+(\cos t)j---(2)\\\\11\bar T'(t)=\sqrt{(-\sin t)^2+(\cos t)^2} \\\\=\sqrt{\sin^2t+\cos^2t} \\\\=1$

$\bar N(t)=\bar T'(t)=\frac{(-\sin t)i+(\cos t)j}{(1)} \\\\ \large \boxed {\bar N(t)=(-\sin t)i+(\cos t)j}$

$K(t)=\frac{|\b\r T'(t)|}{\bar r (t)|} \\\\=\frac{|-\sin t i+\cos t j|}{|7t\cos t +7t \sin t j|}$

Using eq (1) and (2)

$K(t)=\frac{\sqrt{(-\sin t)^2+(\cos t)^2} }{\sqrt{(7t\cos t)^2+(7t\sin t)^2} }\\\\=\frac{\sqrt{\sin^2 t+\cos^2t} }{\sqrt{49t^2(\cos^2 t+\sin^2t)} }\\\\=\frac{\sqrt{1} }{\sqrt{49t^2\times 1} } \\\\ \large \boxed {K(t)=\frac{1}{7t} }$

7 0

3 years ago