Answer: (y-3)^2= 52(x+7)
The focus is (-10, -7) and the directrix is x=16. The y-coordinate of the vertex should be same as the focus(k=-7). Then the x-coordinate of the vertex would be:
p + (-10)= 16 - p
2p= 16 + 10
p=26/2= 13
The x-coordinate of the vertex would be:
h= p+ (-10)
h= 13 - 10= 3
The vertex coordinate would be: (h, k)= (3, -7)
For a vertex (h, k), the formula for equation would be
(y-k)^2=4 p(x-h)
(y-3)^2= 4*13(x--7)
(y-3)^2= 52(x+7)
<span><span>Step by step :
6x</span>−<span>42x</span></span><span>
=<span><span><span>6x</span>+</span>−<span>42x</span></span></span>
<span>=<span><span>6x</span>+<span>−<span>42x</span></span></span></span><span>
=<span>(<span><span>6x</span>+<span>−<span>42x</span></span></span>)</span></span><span>
=<span>−<span>36x</span></span></span>
Hoped I helped!
YEAH fjgjdofckvjdksvlfkfktnfjcjdido
