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marin [14]
3 years ago
12

How are solid , liquid and gas different in volume and mass?

Chemistry
1 answer:
kow [346]3 years ago
5 0

Answer:

Explanation:

Solids have a fixed shape and occupy a fixed volume. because the particles in liquid are so close together,liquids do'not easily compress,so their volume is fixed. gases can also flow, so they occupy the shape of the whole  container.

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The gas in the piston is at constant temperature. A student increases the pressure on the piston from 2 atm to 3 atm. The observ
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Explanation : According to the boyle's law, when the pressure  of the gas molecules are increased from  2 atm to  3 atm creates a decrease in volume of the gas which then increases the rate of collision of the molecules and makes it more compact than it was before.
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The following is what kind of reaction?<br> 2 CH4 +4 02 → 2 CO2 + 4H2O
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<u>It</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>combustion</u><u> </u><u>reaction</u><u>.</u>

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3 years ago
What is the difference between a diatomic molecue and a normal molecue
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7 0
4 years ago
How many grams of sodium acetate ( molar mass = 83.06 g/mol ) must be added to 1.00 Liter of a 0.200 M acetic acid solution to m
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<u>Answer:</u> The mass of sodium acetate that must be added is 30.23 grams

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of acetic acid solution = 0.200 M

Volume of solution = 1 L

Putting values in above equation, we get:

0.200M=\frac{\text{Moles of acetic acid}}{1L}\\\\\text{Moles of acetic acid}=(0.200mol/L\times 1L)=0.200mol

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[\text{salt}]}{[\text{acid}]})  

pH=pK_a+\log(\frac{[CH_3COONa]}{[CH_3COOH]})

We are given:

pK_a = negative logarithm of acid dissociation constant of acetic acid = 4.74

[CH_3COONa]=?mol  

[CH_3COOH]=0.200mol

pH = 5.00

Putting values in above equation, we get:

5=4.74+\log(\frac{[CH_3COONa]}{0.200})

[CH_3COONa]=0.364mol

To calculate the mass of sodium acetate for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of sodium acetate = 83.06 g/mol

Moles of sodium acetate = 0.364 moles

Putting values in above equation, we get:

0.364mol=\frac{\text{Mass of sodium acetate}}{83.06g/mol}\\\\\text{Mass of sodium acetate}=(0.364mol\times 83.06g/mol)=30.23g

Hence, the mass of sodium acetate that must be added is 30.23 grams

7 0
3 years ago
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