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Bezzdna [24]
3 years ago
8

Is the entropy change favorable or not, when a nonpolar molecule is transferred from water to a nonpolar solvent?

Chemistry
1 answer:
jonny [76]3 years ago
8 0

Answer:

Entropy change is favorable when a nonpolar molecule is transferred from water to a nonpolar solvent.

Explanation:

A nonpolar molecule is not miscible in water (polar solvent). Therefore, when mixed together, each specie will cluster together and solvation will not happen.

However, when you tranfer the nonpolar molecule to a nonpolar solvent, the solvent molecules will interact with the nonpolar molecule. This will increase entropy as the level of disorder will increase with solvation.

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Answer:

The final temperature will be close to 20°C

Explanation:

First of all, the resulting temperature of the mix can't be higher than the hot substance's (80°C) or lower than the cold one's (20°C). So options d) and e) are imposible.

Now, due to the high heat capacity of water (4,1813 J/mol*K) it can absorb a huge amount of heat without having a great increment in its temperature. On the other hand, copper have a small heat capacity (0,385 J/mol*K)in comparison.

In conclusion, the copper will release its heat decreasing importantly its temperature and the water will absorb that heat resulting in a small increment of temperature. So the final temperature will be close to 20°C

<u>This analysis can be done because we have equal masses of both substances. </u>

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