Hello,
z=(1/√2-1/√2 i)^6=1/8*(1-i)^6=1/8*(√2∡-45°)^6=1/8*8∡-270°=1∡90°=i
======================================================
Answer:
2x-1=x+1
2x-x=x
1+1=2
x=2
Knowing x's value, we substitute it with the equations
y=x+1
y=2+1
or y=2x-1
y=2(2)-1
y=4-1
y=3
(2,3) are your coordinates :D
Since in a pass code, the placement of the digits is
important, therefore this means that to solve for the total number of
possibilities we have to make use of the principle of Permutation. The formula
for calculating the total number of possibilities using Permutation is given
as:
P = n! / (n – r)!
where,
n = is the total amount of numbers to choose from = 20
r = is the total number of digits needed in the passcode =
4
Therefore solving for the total possibilities P:
P = 20! / (20 – 4)!
P = 20! / 16!
P = 116,280
<span>Hence there are a total of 116,280 possibilities of pass
codes.</span>
To find the area of the larger figure, let's multiply the length by the width.
9 ft * 4 ft = 36ft^2
Let's do the same thing with the smaller figure.
3 ft * 4 ft = 12ft^2
Let's add the area of both figures together.
36ft^2 + 12ft^2 = 48ft^2
Answer:
y = x - 3
<h3>How I know I'm correct:</h3>
if you plug in the numbers from the table, it checks out.
y = x - 3
0 = 3 - 3
0 = 0
y = x - 3
1 = 4 - 3
1 = 1
y = x - 3
2 = 5 - 3
2 = 2
and so on
