Coulomb's law:
F = k×q₁×q₂/r² where k ≈ 9.00×10⁹NC⁻²m²
Given values:
q₁ = +1.0C
q₂ = -1.0C
F = 650N
Substitute the terms in Coulomb's law with our given values. We will have to use the absolute value of q₂ to so the algebra works out. Solve for r:
650 = 9.00×10⁹×1.0×1.0/r²
r = 3721m
Taking significant figures into account:
<h3>r = 3700m</h3>
The Q in the enthalpy of fusion equation stands for heat energy absorbed or released.
<h3>What is enthalpy?</h3>
In thermodynamics, enthalpy is a measure of the heat content of a chemical or physical system.
The enthalpy of fusion is the amount of heat energy required to convert a unit mass of a solid at its melting point into a liquid without an increase in temperature.
Its units are usually Joules per gram (J/g) or calories per gram (cal/g).
The enthalpy of fusion equation is given as follows:
Q = m·ΔHf
Where;
- Q = heat energy
- m = mass
- ΔHf = heat of fusion
Therefore, the Q in the enthalpy of fusion equation stands for heat energy absorbed or released.
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The electrostatic force is 9 x 10¯³ N.
We need to know about electrostatic force to solve this problem. The electrostatic force is applied on a charge which has near position to another charge. It can be determined by
F = k Q1 . Q2 / r²
where F is electrostatic force, k is Coulomb constant (9 x 10⁹ Nm²/C²), Q1 and Q2 are the charges and r is the radius or distance between the charges.
From the question above, we know that
Q1 = -10 nC = -10 x 10¯⁹ C
Q2 = -10 nC = -10 x 10¯⁹ C
r = 1 cm = 0.01 m
By substituting the following parameters, we can calculate the electrostatic force
F = k Q1 . Q2 / r²
F = (9 x 10⁹ . 10 x 10¯⁹ . 10 x 10¯⁹ / (0.01)²
F = 9 x 10¯³ N
Hence, the electrostatic force is 9 x 10¯³ N.
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Which amplitude of the following longitudinal waves has the greatest energy?
amplitude = 10 cm; wavelength = 6 cm; period = 4 seconds
