3 years ago

ANSWER ASAP

Chemistry

1 answer:

ArbitrLikvidat [17]3 years ago

5 0

Answer:

c. 3.00 M HCl

Explanation:

From dilution formula

C1V1 = C2V2

C1=?, V1= 10.0ml, C= 1.5, V2= 20.0ml

Substitute and Simplify

C1×10= 1.5×20

C1= 3.00M

You might be interested in

Identify and calculate the number of representative particles in 2.15 moles of gold.<br>

LekaFEV [45]

Answer:

$1.29 * 10^{24}$ particles of gold

Explanation:

To convert the number of moles of any substance, in this case gold, you need Avogadro's number.

Avogadro's number is always $6.022$ × $10^{23}$

$2.15$ moles Au × $\frac{6.022*10^{23} particles}{1 mole Au}$ = $1.29 * 10^{24}$ particles of gold

5 0

3 years ago

Sibling rivalry may occur when:

sweet [91]

Answer:

Explanation: true

7 0

3 years ago

The expected value for a chemical equation is 47g of water, after an experiment you find that you have 2.58 moles of water. What

strojnjashka [21]

<h3><u>Answer</u>;</h3>

Actual yield = 46.44 g

<h3><u>Explanation;</u></h3>

1 mole of water = 18 g/mol

Therefore;

The experimental yield = 2.58 moles

equivalent to ; 2.58 × 18 = 46.44 g

The theoretical value is 47 g

Percentage yield = 46.44/47 × 100%

= 98.8%

The questions asks for actual yield = 46.44 g

6 0

3 years ago

What is 57.048 rounded to three significant figures?

AnnyKZ [126]

57.0 is it rounded to three sig figs. You count three spaces then round from there, which would be the zero and you would round down because the four is there.

4 0

3 years ago

What is the mass (grams) of salt in 10.0 m' of ocean water? ball park-4x10's (1.000 molsalt -58.44 g salt, 1.0 L ocean water -0.

koban [17]

Answer:

3.5 × 10⁵ g of salt

Explanation:

<em>What is the mass (grams) of salt in 10.0 m³ of ocean water?</em>

We have this data:

1.000 mol salt is equal to 58.44 g salt
1.0 L of ocean water contains 0.60 mol of salt

We will need the following relations:

1 L = 1dm³
1 m³ = 10³ dm³

We can use proportions:

$10.0m^{3} .\frac{10^{3}dm^{3} }{1m^{3} } .\frac{1L}{1dm^{3} } .\frac{0.60molSalt}{1.0L} .\frac{58.44gSalt}{1molSalt} =3.5 \times 10^{5} gSalt$

8 0

3 years ago