Answer:
yqaeh
Explanation:
Electrolysis of acidified water
Water is a poor conductor of electricity, but it does contain some hydrogen ions , H +, and hydroxide ions, OH -. These ions are formed when a small proportion of water molecules naturally dissociate . ... H + ions are attracted to the cathode , gain electrons and form hydrogen gas.
Answer:
The answer to the question is
<h2>
A. Air, Soil, Sand, Water</h2>
Explanation:
Answer:
The mass of the object would be 491.55g/mL. Hope this helped! :)
Explanation:
D= 7.25g/mL M=D•V
V= 67.8mL
M=7.25g/mL•67.8mL
M= 491.55g
The simplest way of separating visible solid impurities that do not dissolve in water from water is by using a sieve (option A).
<h3>What is sieving?</h3>
Sieving is a act of passing substances through a sieve, which is a device with a mesh bottom to separate, in a granular material, larger particles from smaller ones, or to separate solid objects from a liquid.
Sieving is a physical method of separation widely used to separate substances that cannot dissolve in a liquid from that liquid.
Therefore, the simplest way of separating visible solid impurities that do not dissolve in water from water is by using a sieve.
Learn more about sieving at: brainly.com/question/2760394
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For the following reaction, 76.0 grams of barium chloride are allowed to react with 67.0 grams of potassium sulfate.
The reaction consumes _____ moles of barium chloride. The reaction produces _____ moles of barium sulfate and _____ moles of potassium chloride.
Answer: a) The reaction consumes 0.365 moles of barium chloride.
b) The reaction produces 0.365 moles of barium sulfate and 0.730 moles of potassium chloride.
Explanation:
To calculate the moles :
According to stoichiometry :
1 mole of 
require 1 mole of 
Thus 0.365 moles of will require=
of
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
As 1 moles of give = 1 moles of 
Thus 0.365 moles of give = of
As 1 moles of give = 2 moles of 
Thus 0.365 moles of give =
of
Thus the reaction consumes 0.365 moles of barium chloride. The reaction produces 0.365 moles of barium sulfate and 0.730 moles of potassium chloride.
