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Gala2k [10]
3 years ago
11

Use the collision theory to explain how increasing the surface area of a solute will increase the rate of the dissolving process

.
Chemistry
1 answer:
Maksim231197 [3]3 years ago
5 0
<span>More surface area --> more molecules of the solute in contact with the solvent --> more chance for a solvent molecule to collide with the solute molecules --> dissolves faster

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
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Aqueous acetic acid is neutralized by aqueous barium hydroxide. express your answer as a balanced molecular equation. identify a
Studentka2010 [4]

The balanced molecular equation for the given reaction is:

2CH_3COOH(aq) \ + \ Ba(OH)_2(aq) \rightarrow \ Ba(CH_3COO)_2(aq) + 2H_2O(l).

<h3>FURTHER EXPLANATION</h3>

To check that the equation is balanced count how many atoms are present for each element in the reactant and product side. If they are the same before and after reaction for all elements, then the reaction is deemed balanced.

The atom counting for the equation is shown below:

2CH_3COOH(aq) \ + \ Ba(OH)_2(aq) \rightarrow \ Ba(CH_3COO)_2(aq) + 2H_2O(l).

<u>Reactants </u>                  →                 <u>Products</u>

C:  (2 x 2) =4                                  C: (2 x 2) = 4

H: (2 x 4) + (1 x 2) =10                    H: (3 x 2) + (2 X 2) = 10

O: (2 x 2) + (1 x 2) = 6                    O: (2 x 2) + (2 x 1) = 6

Ba: 1                                               Ba: 1

Since the number of atoms of each element are similar in the reactants and products, the equation is balanced.

To determine the state of the substances, consider their solubility.

The reactants are both aqueous (aq) as indicated in the problem.

The first product, Ba(CH_3COO)_2 is aqueous (aq) because based on the solubility rule, it will dissolve in water. Acetates are generally soluble.

The other product is water which will be liquid (l) since it is the solvent used to dissolve the substances.

<h3>LEARN MORE</h3>
  • Solubility Rules brainly.com/question/12984314
  • Net Ionic Equation brainly.com/question/12980075

Keywords: acid-base, neutralization, balancing equations, molecular equation

7 0
3 years ago
Read 2 more answers
An atom gets over all positive charge by ____ _______
Rasek [7]
<h2>Answer:</h2>

Nucleus.

<h2>Explanation:</h2>
  • In an atom the nucleus has an overall positive charge as it contains the protons.
  • Every atom has no overall charge (neutral). While atoms do contain charged particles, they have the same number of positive protons as negative electrons( for example a sodium atom has 11 electrons which are of negative charge and 11 protons which are of positive charge).
  • These opposite charges cancel each other out making the atom neutral.

Result: Nucleus is the overall positive charge of an atom.

4 0
3 years ago
Velocity , Both , Or Acceleration??
ycow [4]
Acceleration is the rate of change and is constantly positive

The answers for Acceleration:
m/s^2
Change in velocity over change in time

Velocity is the speed of the object but also involves direction can be both negative and positive

The answers for Velocity:
m/s
Can be positive or negative
Change in displacement over change in time

Both Acceleration and Velocity:
A rate of change
8 0
3 years ago
A 52.0 g of Copper (specific heat=0.0923cal/gC) at 25.0C is warmed by the addition of 299 calories of energy. find the final tem
Leto [7]

Answer : The final temperature of the copper is, 87.29^oC

Solution :

Formula used :

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

where,

Q = heat gained  = 299 cal

m = mass of copper = 52 g

c = specific heat of copper = 0.0923cal/g^oC      

\Delta T=\text{Change in temperature} 

T_{final} = final temperature = ?

T_{initial} = initial temperature = 25^oC

Now put all the given values in the above formula, we get the final temperature of copper.

299cal=52g\times 0.0923cal/g^oC\times (T_{final}-25^oC)

T_{final}=87.29^oC

Therefore, the final temperature of the copper is, 87.29^oC

4 0
3 years ago
Burning a compound of calcium, carbon, and nitrogen in oxygen in a combustion train generates calcium oxide , carbon dioxide , n
mylen [45]

The question is incomplete, here is the complete question:

Burning a compound of calcium, carbon, and nitrogen in oxygen in a combustion train generates calcium oxide (CaO), carbon dioxide (CO_2), nitrogen dioxide (NO_2), and no other substances. A small sample gives 2.389 g CaO, 1.876 g CO_2, and 3.921 g NO_2 Determine the empirical formula of the compound.

<u>Answer:</u> The empirical formula for the given compound is CaCN_2

<u>Explanation:</u>

The chemical equation for the combustion of compound having calcium, carbon and nitrogen follows:

Ca_xC_yN_z+O_2\rightarrow CaO+CO_2+NO_2

where, 'x', 'y' and 'z' are the subscripts of calcium, carbon and nitrogen respectively.

We are given:

Mass of CaO = 2.389 g

Mass of CO_2=1.876g

Mass of NO_2=3.921g

We know that:

Molar mass of calcium oxide = 56 g/mol

Molar mass of carbon dioxide = 44 g/mol

Molar mass of nitrogen dioxide = 46 g/mol

<u>For calculating the mass of carbon:</u>

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 1.876 g of carbon dioxide, \frac{12}{44}\times 1.876=0.5116g of carbon will be contained.

<u>For calculating the mass of nitrogen:</u>

In 46 g of nitrogen dioxide, 14 g of nitrogen is contained.

So, in 3.921 g of nitrogen dioxide, \frac{14}{46}\times 3.921=1.193g of nitrogen will be contained.

<u>For calculating the mass of calcium:</u>

In 56 g of calcium oxide, 40 g of calcium is contained.

So, in 2.389 g of calcium oxide, \frac{40}{56}\times 2.389=1.706g of calcium will be contained.

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Calcium =\frac{\text{Given mass of Calcium}}{\text{Molar mass of Calcium}}=\frac{1.706g}{40g/mole}=0.0426moles

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.5116g}{12g/mole}=0.0426moles

Moles of Nitrogen = \frac{\text{Given mass of Nitrogen}}{\text{Molar mass of Nitrogen}}=\frac{1.193g}{14g/mole}=0.0852moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0426 moles.

For Calcium = \frac{0.0426}{0.0426}=1

For Carbon = \frac{0.0426}{0.0426}=1

For Nitrogen = \frac{0.0852}{0.0426}=2

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of Ca : C : N = 1 : 1 : 2

Hence, the empirical formula for the given compound is CaCN_2

3 0
3 years ago
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