What would be the major product obtained from hydroboration–oxidation of the following alkenes?
1 answer:
Answer:
a. 3-methylbutan-2-ol
b. 2-methylcyclohexan-1-ol
Explanation:
For this reaction, we must remember that the hydroboration is an <u>"anti-Markovnikov" reaction</u>. This means that the "OH" will be added at the <em>least substituted carbon of the double bond.</em>
In the case of <u>2-methyl-2-butene</u>, the double bond is between carbons 2 and 3. Carbon 2 has two bonds with two methyls and carbon 3 is attached to 1 carbon. Therefore <u>the "OH" will be added to carbon three</u> producing <u>3-methylbutan-2-ol</u>.
For 1-methylcyclohexene, the double bond is between carbons 1 and 2. Carbon 1 is attached to two carbons (carbons 6 and 7) and carbon 2 is attached to one carbon (carbon 3). Therefore<u> the "OH" will be added to carbon 2</u> producing <u>2-methylcyclohexan-1-ol</u>.
See figure 1
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4 moles
Explanation:
Given parameters:
number of moles of reacting NO = 24moles
Equation of the reaction:
4C₃H₆ + 6NO ⇒ 4C₃H₃N + H₂O + N₂
Solution:
The moles is synonymous the quantity of matter that contains the avogadro's number of particles.
To solve this problem, we must ensure that the given equation is balanced by simply inspecting.
The equation is balanced by inspection.
From the balanced equation;
6 moles of NO reacted to produce 1 mole of nitrogen gas
24 moles of NO will therefore produce = 4 moles
learn more:
Number of moles brainly.com/question/1841136
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