All categories

3 years ago

What would be the major product obtained from hydroboration–oxidation of the following alkenes?

Chemistry

1 answer:

zmey [24]3 years ago

8 0

Answer:

a. 3-methylbutan-2-ol

b. 2-methylcyclohexan-1-ol

Explanation:

For this reaction, we must remember that the hydroboration is an "anti-Markovnikov" reaction. This means that the "OH" will be added at the least substituted carbon of the double bond.

In the case of 2-methyl-2-butene, the double bond is between carbons 2 and 3. Carbon 2 has two bonds with two methyls and carbon 3 is attached to 1 carbon. Therefore the "OH" will be added to carbon three producing 3-methylbutan-2-ol.

For 1-methylcyclohexene, the double bond is between carbons 1 and 2. Carbon 1 is attached to two carbons (carbons 6 and 7) and carbon 2 is attached to one carbon (carbon 3). Therefore the "OH" will be added to carbon 2 producing 2-methylcyclohexan-1-ol.

See figure 1

I hope it helps!

You might be interested in

3. Is the following statement a fact, opinion or theory? Why?

Nesterboy [21]

This is an opinion. The person believes that eggs are better than cereal for breakfast. When someone else might disagree with that and say that cereal is better then eggs for breakfast.

7 0

3 years ago

What is the moment for the left hand side of this balance?

aleksklad [387]

Answer:

Explanation:

6 (weights) x 3 (distance) = moment

5 0

3 years ago

A student mixes a 10.0 mL sample of 1.0 M NaOH with a 10.0 mL sample of 1.0 M HCl in a polystyrene container. The temperature of

ElenaW [278]

Answer:

The experimental value of ΔH is -50 kJ/mol

Explanation:

Step 1: Data given

Volume of 1.0 M NaOH = 10.0 mL = 0.01 L

Volume of 1.0 M HCl = 10.0 mL = 0.01 L

Temperature before mixing = 20 °C

Final temperature = 26 °C

Specific heat of solution = 4.2 J/g°C

Density = 1g/mL

Step 2: Calculate q

q = m*c*ΔT

⇒ with m = the mass

⇒ 20.0 mL * 1g/mL = 20 grams

⇒ c = specific heat of solution = 4.2 J/g°C

⇒ ΔT = T2 -T1 = 26 -20 = 6 °C

q = 20g * 4.2 J/g°C * 6°C

q = 504 J

ΔHrxn = -q ( because it's an exothermic reaction)

ΔHrxn = -504 J

Step 3: Calculate number of moles

Moles = Molarity * volume

Moles = 1M *0.01 L = 0.01 moles

Step 4: Calculate the experimental value of ΔH

ΔHrxn = -504 / 0.01 mol = -50400 J/mol = -50.4 kJ/mol

The experimental value of ΔH is -50 kJ/mol

6 0

4 years ago

¿Cuál de los siguientes no acelera a una reacción?

max2010maxim [7]

Answer:

The correct answer is B).

Explanation:

The factors that accelerate a chemical reaction are:

- Temperature: at a higher temperature, the speed of a reaction is increased.

- Pressure: the higher this is, the greater the collisions between molecules and an acceleration of the reaction speed will occur.

-Catalysts: correspond to substances that accelerate chemical reactions, an example are enzymes. There are catalysts that increase the reaction rate and others that generate the opposite effect (they are inhibitors).

There are also other factors that accelerate a chemical reaction such as the concentration of reagents.

7 0

4 years ago

What are the 3 primary consumers and what are the 3 secondary consumers

goldenfox [79]

Primary:
Grasshopper
Mouse
Grass

Secondary:
Hawk
Snake
Coyote

8 0

3 years ago