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2 years ago

How many atoms are in 2.12 mole of propane

Chemistry

2 answers:

artcher [175]2 years ago

6 0

Answer:

More exactly this number is 6.02 x 1023 10 2 3 .

Kitty [74]2 years ago

6 0

It happens when you multiply the numbers

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Determine the free energy(ΔG) from the standard cell potential (Ecell0 ) for the reaction:2ClO2-(aq)+Cl2(g)→2ClO2(g)+ 2Cl-(aq)wh

Dima020 [189]

Answer: The $\Delta G^o$ for the given reaction is $-7.84\times 10^4J$

Explanation:

For the given chemical reaction:

$2ClO_2^-(aq.)+Cl_2(g)\rightarrow 2ClO_2(g)+2Cl^-(aq.)$

Half reactions for the given cell follows:

Oxidation half reaction: $ClO_2^-\rightarrow ClO_2+e^-;E^o_{ClO_2^-/ClO_2}=0.954V$ ( × 2)

Reduction half reaction: $Cl_2+2e^-\rightarrow 2Cl(g);E^o_{Cl_2/2Cl^-}=1.36V$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=1.36-(0.954)=0.406V$

To calculate standard Gibbs free energy, we use the equation:

$\Delta G^o=-nFE^o_{cell}$

Where,

n = number of electrons transferred = 2

F = Faradays constant = 96500 C

$E^o_{cell}$ = standard cell potential = 0.406 V

Putting values in above equation, we get:

$\Delta G^o=-2\times 96500\times 0.406=-78358J=-7.84\times 10^4J$

Hence, the $\Delta G^o$ for the given reaction is $-7.84\times 10^4J$

4 0

2 years ago

A teacher attaches two slinky springs to a fixed support. The springs are moved, as shown in the image. Wave A wave B What prope

Misha Larkins [42]

Answer:

a changes more because it going higher

Explanation:

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(sand) and (Sand with water) both of them are heterogeneous mixture isn't it?

patriot [66]

Answer:

yes true

Explanation:

both are heterogeneous

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AlekseyPX

Answer:

Elecric charge/ Electricity

Explanation:

Electric charge is the net gain or loss of electrons

I hope im right!!

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If the pressure, volume, and temperature of a gas are known, which can most likely be found by using the ideal gas law?

Radda [10]

Standard temperature and pressure

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