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Artemon [7]
3 years ago
14

At higher temperatures,

Chemistry
1 answer:
valentinak56 [21]3 years ago
3 0

Answer:

reaction rates increase because reactants move faster, collide more often, and produce more collisions with the required energy of activation.

Explanation:

<em>A</em><em>t</em><em> </em><em>h</em><em>i</em><em>g</em><em>h</em><em>e</em><em>r</em><em> </em><em>t</em><em>e</em><em>m</em><em>p</em><em>e</em><em>r</em><em>a</em><em>t</em><em>u</em><em>r</em><em>e</em><em>s</em><em>,</em><em> </em>the reactant atoms gain high kinetic energy which decreases the intermolecular forces of attraction between these atoms/molecules.

Hence the rate of collision is very high which decreases the activation energy and products are formed with in a short period of time.

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3 years ago
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There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In
adell [148]

Answer:

The net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide is 523.2 kJ.

Explanation:

Step 1:

CaC_2(s) + 2H_2O(g)\rightarrow C_2H_2(g) + Ca(OH)_2(s),\Delta H_1=414.0 kJ...[1]

Step 2 :

6C_2H_2(g) + 3CO_2(g) + 4H_2O(g)\rightarrow 5CH_2CHCO_2H(g) \Delta H_2=132.0kJ..[2]

Adding 6 × [1] and [2]:

6CaC_2(s) + 12H_2O(g)\rightarrow 6C_2H_2(g) + 6Ca(OH)_2(s)

6C_2H_2(g)+3CO_2(g)+16H_2O(g)\rightarrow 5CH_2CHCO_2H(g)

we get :

6CaC_2(s) + 8H_2O(g)+3CO_2(g)\rightarrow 5CH_2CHCO_2H(g)+ 6Ca(OH)_2(s),\Delta H'=?

\Delta H'=6\times \Delta H_1+\Delta H_2

\Delta H'=6\times 414.0 kJ+132.0kJ

\Delta H'=2,626 kJ

Energy released on formation of 5 moles of acrylic acid = 2,626 kJ

Energy released on formation of 1 mole of acrylic acid:

\frac{ 2,626 kJ}{5 } = 523.2 kJ

7 0
4 years ago
Diagonal lines in the graph represent the temperature of the substance is ___.
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3 years ago
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7 0
3 years ago
18. How many moles of atoms are there in each of
Lelechka [254]

a) 1 mole of Ne

b) i/2 mole of Mg

c) 1570 moles of Pb.

d) 2.18125*10^-13 moles of oxygen.

                     

Explanation:

The number of moles calculated by Avogadro's number in 6.23*10^23 of Neon.

6.23*10^23= 1/ 6.23*10^23

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The number of moles calculated by Avogadro's number in 3.01*10^23 of  Mg

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                = 1/2 moles of Pb.

Number of moles in 3.25*10^5 gm of lead.

atomic weight of Pb=

n=weight/atomic weight

  = 3.25*10^5/ 207

  = 1570 moles of Pb.

Number of moles 4.50 x 10-12 g O

number of moles= 4.50*10^-12/16

                            =  2.18125*10^-13 moles of oxygen.

3 0
3 years ago
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