A line that is parallel has the same slop where a line that is perpendicular has a slop that is negative and reciprocal.
so for the parallel one you don't need to worry about the slop because it will be 2/3x. But yous the point slope equation form
y-y1=m(x-x1)
y+5=2/3(x+2)
y+5=2/3x+ 4/3
y=2/3x-11/3
-2/3x+y=-11/3
multiple by -1 so A inst negative
2/3-y=11/3
For a line that is perpendicular you just need to flip the original 2/3x slope and make it negative.
y+5=-3/2(x+2)
y+5=-3/2x-3
y=-3/2x-8
3/2x+y=-8
<span>Find the equation of the line that passes through the points (3,-2) and (4,5).</span>
5-(-2)=7/ 4-3=1
So the slope is 7. Now plugin 7 for "m" and use one of the two points for x and y
5=7(4)*b
5=28*b
5-28=b
-23=b
So y=7x-23
Answer:
-$73.73
Step-by-step explanation:
To get this answer, we must subtract 23.73 from -50, as Mr. Alexander is losing money by spending. Once we subtract, we get -73.73 dollars.
Hope this helps!
Answer:
m∠A = 50°
m∠E = 50°
Step-by-step explanation:
7x - 17 and 2x + 8 are same side exterior angles. They have a sum of 180°.
7x - 17 + 2x + 8 = 180
9x - 9 = 180
9x = 189
x = 21
∠A and 7x - 17 are supplementary. ∠E and 2x + 8 are vertical angles.
m∠A + 7x - 17 = 180
m∠A + 7(21) - 17 = 180
m∠A + 147 - 17 = 180
m∠A + 130 = 180
m∠A = 50
m∠E = 2x + 8
m∠E = 2(21) + 8
m∠E = 42 + 8
m∠E = 50
Answer:
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