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lisabon 2012 [21]
4 years ago
3

A stovetop burner on medium reaches 95°C. Which will also receive a flow of heat directly from the burner? the surrounding air a

burner at the same temperature a pan heated to 100°C hotter water inside a pan
Physics
2 answers:
Pavel [41]4 years ago
6 0

Answer:

Option C, a pan heated to 100°C

Explanation:

The pan on the burner will be in direct contact of the heat released by burner and hence the pan will receive the direct flow of heat from the burner.

However, the water is the pan will be heated by the heat transferred from the pan to the water in it. Water will not receive heat directly from the burner.

Hence, option C is correct

spayn [35]4 years ago
6 0

Answer:

<h2><u>C or 3    </u></h2><h3><u>a pan heated to 100°C</u></h3>

Explanation:

I have proof that it it most likely right with a side of memes.

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Rapid energy transfer between ____ and ____ energy make roller coasters thrilling
icang [17]
Hello there!

The answer is the following:

Rapid energy transfer between Potential and Kinetic energy makes roller coasters thrilling. 

Potential Energy is the energy related to the vertical position of the roller coaster cart. When it is at the highest point, the Potential Energy is at a maximum. 

Kinetic Energy is the energy related to the speed of the roller coaster cart. When the cart is at the highest point, the kinetic energy is at a minimum, but as it begins to go down, the Potential Energy is transformed into Kinetic Energy, making the cart to increase its speed and making it a thrilling experience. 
4 0
3 years ago
Energy that is associated with the position or composition of an object is called
Pani-rosa [81]
That is potential energy.
4 0
3 years ago
Den pushes a desk 400 cm across the floor. He exerts a force of 10 N for 8 s to move the desk.
stellarik [79]

Answer: The correct option is Option b.

Explanation:

Power is defined as the rate of work done by an object.

Mathematically,

P=\frac{W}{t}    .....(1)

And work done is the product of force exerted on the object times the displacement covered by that object.

Mathematically,

W=F.s

Putting this value in above equation, we get:

P=\frac{F.s}{t}

where,

P = power = ?W

F = Force exerted = 10N

s = Displacement = 400cm = 4m   (Conversion factor: 1m = 100 cm)

t = Time taken = 8s

Putting values in above equation, we get

P=\frac{10\times 4}{8}\\\\P=5W

Hence, the correct option is Option b.

7 0
4 years ago
Read 2 more answers
Three identical balls are thrown from the same height off a tall building. They are all thrown with the same speed, but in diffe
koban [17]

Answer:

three balls have the same speed

Explanation:

In a parabolic motion we have that

v_{x}=v_{0}cos\alpha\\v_{y}=-gt+v_{0}sin\alpha\\v=\sqrt{v_{x}^{2}+v_{y}^{2}}\\

but the time just before the balls hit the ground is

t=\frac{2v_{0}sin\alpha}{g}

Hence we have

ball A

v=\sqrt{v_{0}^{2}cos^{2}(0)+(-g\frac{2v_{0}sin(0)}{g}+v_{0}sin(0))^{2}}\\v=\sqrt{v_{0}^{2}}=v_{0}

ball B

v=\sqrt{v_{0}^{2}cos^{2}(45)+(-g\frac{2v_{0}sin(45)}{g}+v_{0}sin(45))^{2}}\\v=\sqrt{v_{0}^{2}(\frac{\sqrt{2}}{2})^{2}+v_{0}^{2}(\frac{\sqrt{2}}{2})^{2}}\\v=\sqrt{v_{0}^{2}}=v_{0}

ball C

v=\sqrt{v_{0}^{2}cos^{2}(-45)+(-g\frac{2v_{0}sin(-45)}{g}+v_{0}sin(-45))^{2}}\\v=\sqrt{v_{0}^{2}(\frac{\sqrt{2}}{2})^{2}+v_{0}^{2}(\frac{\sqrt{2}}{2})^{2}}\\v=\sqrt{v_{0}^{2}}=v_{0}

Hence, all three balls have the same speed just before hit the groug

vA=vB=vC

I hope this is useful for you

regards

5 0
3 years ago
A spring, having an unstretched length of 2ft, has one end attached to the 10lb ball. determine the angle ? of the spring if the
Ganezh [65]
The angle theta of the spring is 31 degrees. To solve for this, show the equation which is equal to the 10lb ball. With this, the unknown will be the angle. Then transpose/transfer the terms in order to isolate the variable for the angle. First solve for s, then solve for angle theta. You will come up with s = .5849 ft and angle theta = 31.2629 or 31 degrees. Hope this helps.
5 0
4 years ago
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