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bija089 [108]
3 years ago
10

Suppose that when spring was wound, 100J of work was done but 15J escaped to the surrounding as heat. The change in internal ene

rgy of the spring is? ​
Physics
1 answer:
zzz [600]3 years ago
5 0

Answer: 85J

Explanation:

From the question, we are informed that when spring was wound, 100J of work was done but 15J escaped to the surrounding as heat.

Therefore, the change in internal energy of the spring will be calculated as:

ΔU = q + w

where, q = -15J

w = 100J

ΔU = -15J + 100J

= 85J

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Answer: 1.22 m

Explanation:

The equation of motion in this situation is:

y=y_{o}+V_{oy}t-\frac{g}{2}t^{2} (1)

Where:

y=0 is the final height of the ball

y_{o}=h is the initial height of the ball

V_{oy}=V_{o}sin(0\°)=0 is the vertical component of the initial velocity (assuming the ball was thrown vertically and there is no horizontal velocity)

t=0.5 s is the time at which the ball lands

g=9.8 m/s^{2} is the acceleration due gravity

So, with these conditions the equation is rewritten as:

h=\frac{g}{2}t^{2} (2)

h=\frac{9.8 m/s^{2}}{2}(0.5 s)^{2} (3)

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h=1.22 m

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<em></em>

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