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bagirrra123 [75]
4 years ago
5

BRAINLIEST ANSWER.... How many bonding and nonbonding electrons are on the nitrogen atom in NO2?

Chemistry
1 answer:
ioda4 years ago
5 0

The answer would be C there would be 6 nonbonding electrons and 2 bonding electrons.

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How natural plants and wetlands purify water
DedPeter [7]
Plants and wetlands purify water by acting as filter media. The roots of the plants and the wetlands would trap pollutants like sediments and hold onto the. In wetlands, the flow of water is slow allowing for the sediments to settle due to gravity onto the bottom where the plants would accumulate them into place. With this, excess nutrients would be remove and will prevent polluting bodies of water. Also, bacteria like E. coli and Salmonella can be filtered out from the water. There are plants that works excellent for filtering out pollutants like the lilies, hornwort, bulrushes and rushes.
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3 years ago
Pls help me 20 points ty
qaws [65]

Answer:

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Explanation:

6 0
3 years ago
Read 2 more answers
2.0 L of Carbon dioxide is heated from -25.0 °C to Standard Temperature.
RideAnS [48]

The final volume of the gas that was heated from -25.0 °C to standard temperature is 2.2L.

<h3>How to calculate volume?</h3>

The volume of a given gas can be calculated using the Charles law equation as follows:

V1/T1 = V2/T2

Where;

  • V1 = initial volume
  • V2 = final volume
  • T1 = initial temperature
  • T2 = final temperature

  • V1 = 2L
  • V2 = ?
  • T1 = -25°C + 273 = 248K
  • T2 = 273K

2/248 = V2/273

273 × 2 = 248V2

546 = 248V2

V2 = 546/248

V2 = 2.2L

Therefore, the final volume of the gas that was heated from -25.0 °C to standard temperature is 2.2L

Learn more about volume at: brainly.com/question/11464844

5 0
2 years ago
How much energy (kJ) is required to change 0.18 mole of ice (s) at 0 C to water (l) at 0 C?
Dmitriy789 [7]

Answer:25,06 kJ of energy must be added to a 75 g block of ice.

ΔHfusion(H₂O) = 6,01 kJ/mol.

T(H₂O) = 0°C.

m(H₂O) = 75 g.

n(H₂O) = m(H₂O) ÷ M(H₂O).

n(H₂O) = 75 g ÷ 18 g/mol.

n(H₂O) = 4,17 mol.

Q = ΔHfusion(H₂O) · n(H₂O)

Q = 6,01 kJ/mol · 4,17 mol

Q = 25,06 kJ.

Explanation:

6 0
3 years ago
Dependent variable? ( what did we measore)?
lana66690 [7]
The thing u change.
6 0
3 years ago
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