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Shalnov [3]
3 years ago
11

Changing the pendulum design after the first trial was an example of _____________ to solve the problem presented by the teacher

. A) designing the model B) evaluating th e model C) identifying the problem D) doing research on the problem
Chemistry
2 answers:
docker41 [41]3 years ago
6 0

Answer:

C. identifying the problem

Explanation:

To be sure of what the experiment involves one need to have an hypothesis to guide the task.

Assuming the hypothesis in the experiment is , “changing the amount of weight at the end of the pendulum will change the period of the pendulum.”

The experiment design would be complementary in that it would entail measuring the period with just one amount of weight, then changing the weight without changing any other variables, then measuring the period with the new amount of weight.

Changing the pendulum design after the first trial was an example of identifying the problem or the variable tied to the one factor that we are solving for.

Luden [163]3 years ago
3 0

Answer:

Changing the pendulum design after the first trial was an example of <u>evaluating the model</u> to solve the problem presented by the teacher.

Explanation:

A model constitutes an abstract representation of a certain aspect of reality, and has a structure that is formed by the elements that characterize the aspect of the modeled reality and by the relationships between these elements.

This achieved result provides a better understanding of the problem being studied, offering aspects that can be changed or improved to solve the problem posed, obtaining more information about the reality of the phenomenon that is being represented.

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Which of these molecules is nonpolar?<br> a.CH3CI<br> b.CO<br> c.O2<br> d.PF3
valentina_108 [34]

Answer:

i think the answer is D

Explanation:

7 0
2 years ago
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What is the solubility product expression for Ag2CO3
Dominik [7]
<span> Ksp = [Ag+]^2[CO32-]that should be it </span>
7 0
3 years ago
How is electronegativity related to covalent bonding?
Zolol [24]

Answer:

Atoms must have similar electronegativities in order to share electrons in a covalent bond.

Explanation:

Covalent bonding is one of the bondings that occurs between the atoms of elements. It is the bonding in which atoms share their valence electrons with one another. However, the ELECTRONEGATIVITY, which is the ability of an atom to be attracted to electrons play a major role in the formation of covalent bonds.

When atoms of different electronegativities combine, the more electronegative atom pulls more electrons towards itself, hence, an IONIC bond is formed. However, when the electronegativities of the atoms are similar, the sharing of their electrons becomes stronger. Hence, ATOMS MUST HAVE SIMILAR ELECTRONEGATIVITIES in order to share electrons in a covalent bond.

5 0
3 years ago
Read 2 more answers
The two naturally occuring isotopes of antimony are 121Sb (57.21%) and 123Sb (42.79%), with isotopic masses of 120.904 and 122.9
emmasim [6.3K]

Answer:

The average atomic weight = 121.7598 amu

Explanation:

The average atomic weight of natural occurring antimony can be calculated as follows :

To calculate the average atomic mass the percentage abundance must be converted to decimal.

121 Sb has a percentage abundance of 57.21%, the decimal format will be

57.21/100 = 0.5721 . The value is the fractional abundance of 121 Sb .

123 Sb has a percentage abundance of 42.79%, the decimal format will be

42.79/100 = 0.4279. The value is the fractional abundance of 123 Sb .

Next step is multiplying the fractional abundance to it masses

121 Sb = 0.5721 × 120.904 = 69.169178400

123 Sb = 0.4279 × 122.904 = 52.590621600

The final step is adding the value to get the average atomic weight.

69.169178400 + 52.590621600 = 121.7598 amu

5 0
3 years ago
What is oxidized in a galvanic cell with aluminum and gold electrodes ?
k0ka [10]

Answer:

Aluminum metal

Explanation:

In order to properly answer this or a similar question, we need to know some basic rules about galvanic cells and standard reduction potentials.

First of all, your strategy would be to find a trusted source or the table of standard reduction potentials. You would then need to find the half-equations for aluminum and gold reduction:

Al^{3+}+3e^-\rightarrow Al; E^o=-1.66 V

Au^{3+}+3e^-\rightarrow Au; E^o=1.50 V

Since we have a galvanic cell, the overall reaction is spontaneous. A spontaneous reaction indicates that the overall cell potential should be positive.

Since one half-equation should be an oxidation reaction (oxidation is loss of electrons) and one should be a reduction reaction (reduction is gain of electrons), one of these should be reversed.

Thinking simply, if the overall cell potential would be obtained by adding the two potentials, in order to acquite a positive number in the sum of potentials, we may only reverse the half-equation of aluminum (this would change the sign of E to positive):Al\rightarrow Al^{3+}+3e^-; E^o=1.66 V\\Au^{3+}+3e^-\rightarrow Au; E^o=1.50 V

Notice that the overall cell potential upon summing is:

E_{cell}=1.66 V + 1.50 V=3.16 V

Meaning we obey the law of galvanic cells.

Since oxidation is loss of electrons, notice that the loss of electrons takes place in the half-equation of aluminum: solid aluminum electrode loses 3 electrons to become aluminum cation.

6 0
3 years ago
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