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Shalnov [3]
3 years ago
11

Changing the pendulum design after the first trial was an example of _____________ to solve the problem presented by the teacher

. A) designing the model B) evaluating th e model C) identifying the problem D) doing research on the problem
Chemistry
2 answers:
docker41 [41]3 years ago
6 0

Answer:

C. identifying the problem

Explanation:

To be sure of what the experiment involves one need to have an hypothesis to guide the task.

Assuming the hypothesis in the experiment is , “changing the amount of weight at the end of the pendulum will change the period of the pendulum.”

The experiment design would be complementary in that it would entail measuring the period with just one amount of weight, then changing the weight without changing any other variables, then measuring the period with the new amount of weight.

Changing the pendulum design after the first trial was an example of identifying the problem or the variable tied to the one factor that we are solving for.

Luden [163]3 years ago
3 0

Answer:

Changing the pendulum design after the first trial was an example of <u>evaluating the model</u> to solve the problem presented by the teacher.

Explanation:

A model constitutes an abstract representation of a certain aspect of reality, and has a structure that is formed by the elements that characterize the aspect of the modeled reality and by the relationships between these elements.

This achieved result provides a better understanding of the problem being studied, offering aspects that can be changed or improved to solve the problem posed, obtaining more information about the reality of the phenomenon that is being represented.

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What is the mass of the object?
galben [10]

Answer:

37.3

263.5

Explanation:

The scale measures hundreds of units, tens of units, units, and parts of units (1 decimal place.

Scale 1

Hundreds 0 * 100 = 0

Tens: 3 * 10 = 30

Units: 7 * 1 = 7

1/10 unit = 3* 0.1 = 0.3

Total 30 + 7 + 0.3 = 37.3

Scale 2

Hundreds 2 * 100 = 200

Tens: 6 * 10 = 60

Units: 3 * 1 = 3

1/10 unit = 5* 0.1 = 0.5

Total = 200 + 60 + 3 + 0.5 = 263.5

7 0
3 years ago
Give the o.N. Of each of the elements magnesium and oxygen in the reactants and in the products 2Mg + O2=2MgO
vlada-n [284]

Answer:

2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}

Explanation:

Hello there!

In this case, according to the rules for the oxidation states in chemical reactions, it is possible to realize that lone elements have 0 and since magnesium is in group 2A, it forms the cation Mg⁺² as it loses electrons and oxygen is in group 6A so it forms the anion O⁻²; therefore resulting oxidation numbers are:

2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}

Best regards!

4 0
2 years ago
A chemist measures the enthalpy change ?H during the following reaction: Fe (s) + 2HCl (g) ? FeCl2 (s) + H2 (g) =?H?157.kJ Use t
erik [133]

Correct Question:

A chemist measures the enthalpy change ΔH during the following reaction: Fe(s) + 2HCl(g)-->FeCl2(s) + H2 ΔH=-157.0 kJ. Use this information to complete the table below. Round each of your answers to the nearest kJ/mol

Answer:

-314 kJ

+628 kJ

+157 kJ

Explanation:

The enthalpy change of a reaction measures the amount of heat that is lost or gained by it. If ΔH >0 the heat is gained, and the reaction is called endothermic, if ΔH<0, the heat is lost, and the reaction is called exothermic.

If the reaction is inverted, the value of ΔH is inverted too (the opposite endothermic reaction is exothermic), and if the reaction is multiplied by a constant, ΔH will be multiplied by it too.

1) 2Fe(s) + 4HCl --> 2FeCl2(s) + 2H2(g)

This reaction is the product of the given reaction by 2, so

ΔH = 2*(-157) = -314 kJ

2) 4FeCl2(s) + 4H2(g) --> 4Fe(s) + 8HCl(g)

This reaction is the inverted reaction given multiplied by 4, so

ΔH = 4*(157) = +628 kJ

3) FeCl2(s) + H2(g) --> Fe(s) + 2HCl

This reaction is the inverted reaction given, so

ΔH = +157 kJ

4 0
3 years ago
What is the mass number of an atom or ion with three protons, three neutrons, and three electrons?.
____ [38]

Answer:

the mass number of the atom or ion is 6

5 0
3 years ago
What is the mass of 4.56 moles of copper (ii) fluoride​
musickatia [10]

Answer:

463.0 g.

Explanation:

  • We can use the following relation:

<em>n = mass/molar mass.</em>

where, n is the mass of copper(ii) fluoride​ (m = 4.56 mol),

mass of copper(ii) fluoride​ = ??? g.

molar mass of copper(ii) fluoride​ = 101.543 g/mol.

∴ mass of copper(ii) fluoride​ = (n)(molar mass) = (4.56 mol)(101.543 g/mol) = 463.0 g.

7 0
3 years ago
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